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3 years ago

In humans, which part of the brain contains 80 percent of its weight? cerebrum cerebellum spiral cord brain stem

Physics

2 answers:

777dan777 [17]3 years ago

7 0

Answer:

Cerebrum

Explanation:

Human brain is defined as the centralized organ of the human nervous system and the spinal cord is connected to the central nervous system.

The cerebrum, brainstem, and the cerebellum are the main parts of human brain. Out of these the cerebrum is the largest part of the human brain which consists or can say that which is divided into two cerebral hemisphere.

Outer layer of grey matter which is present in cerebrum is known as cerebral cortex and this cortex covers the white matter. Then the cortex is further divided into neocortex and the allocortex.

So, because of the largest part of the brain it covers approximately 80 percent of human weight.

Therefore, cerebrum is the part of human brain which consists 80 percent of its weight.

kolezko [41]3 years ago

6 0

I believe it's the Cerebrum.

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Li is riding her bicycle at 8.0 m/s. She slows down to 4.0 m/s. Her change in velocity is m/s. If Li takes 2 seconds to make thi

forsale [732]

You will have to use this formula:
$v = vo + a \times t$

Final Velocity (V) = 4m/s
Initial Velocity (Vo) = 8m/s
Acceleration (a) = ? m/s^2
Time (t) = 2 secs

Then:

-> 4 = 8 + a x 2
-> 4 - 8 = 2a
-> -4 = 2a
-> a = -4/2
-> a = -2 m/s^2

Ps: It's value is negative because the she was in retrograde motion.

Answer: Her acceleration is -2 m/s^2.

4 0

4 years ago

Read 2 more answers

A man holds a child on his shoulders while watching a football match. How many work has he done if the game lasts for 2 hours?

Shalnov [3]

very interesting and amazing question u had asked but i get it...

Answer

work done is given by

W = Force × Displacement

but in above case force is exerted on the men as the weight of the child × gravitational pull of earth (9.8 m/s^2) but the displacement or movement is ZERO
there for W= F×0 =0
so even after carrying child for 2 hours work done by the men will be zero

More examples

a person standing straight and lifting weight
a person carry some weight and walk in a circular path and came back to its original position.........in this case also Displacement will be zero

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hope it helped u buddy

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3 years ago

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You are In-line skates at the top of a small hill. Your potential energy is equal to 1000 J. The last time we checked, your mass

stira [4]

A) Weight = mass × acceleration (due to gravity)

= 60×9.8

= 588 N

B) Potential energy = mass x gravity x change in height

1,000 = 60.0 x 9.8 x h

h = 1.7 m

C) Kinetic energyF = potential energyI

KEF = 1/2mv2

PEI = mgh = 1,000 J

1/2mv2 = 1,000

1/2(60.0)v2 = 1,000

v2 = 33.33

v = 5.77 m/s

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4 years ago

A projectile of mass 6.8 kg kg is shot horizontally with an initial speed of 14.5 m/s from a height of 26.7 m above a flat deser

sleet_krkn [62]

Answer:

Explanation:

Given

mass of projectile $m=6.8\ kg$

initial horizontal speed $u_x=14.5\ m/s$

height $h=26.7\ m$

Considering vertical motion

velocity gained by projectile during 26.7 m motion

$v^2-u^2=2 as$

v=final velocity

u=initial velocity

a=acceleration

s=displacement

$v^2-(0)^2=2\times (9.8)\times (26.7)$

$v=\sqrt{523.32}$

$v=22.87\ m/s$

Horizontal velocity will remain same as there is no acceleration

final velocity $v_{net}=\sqrt{(v)^2+(u_x)^2}$

$v_{net}=\sqrt{733.57}=27.08\ m/s$

Initial kinetic Energy $K_i=\frac{1}{2}mu_x^2$

$K_i=\frac{1}{2}\times 6.8\times (14.5)^2=714.85\ J$

Final Kinetic Energy $K_f=\frac{1}{2}mv_{net}^2$

$K_f=\frac{1}{2}\times 6.8\times (27.08)^2$

$K_f=2493.30\ J$

Work done by all the force is equal to change in kinetic Energy of object

Work done by gravity is $W_g$

$W_g=\Delta K$

$W_g=2493.30-714.85=1778.45\ J$

8 0

3 years ago

the second question. the answer to the first part is 616. pls i have a 34 on the assignment rn pls help

Marat540 [252]

Answer:

a) Ffloor = 616.56[N]

b) Ffloor = 484.16 [N]

Explanation:

In order to solve this problem, we must first make a free body diagram. In this free body diagram include forces, as well as acceleration.

Then after the free body diagram, we perform a force analysis by means of Newton's second law, where the upward forces and even the upward acceleration will be taken as positive.

ΣF = m*a

where:

F = force [N] (units of Newtons]

m = mass [kg]

a = acceleration [m/s²]

g = gravity acceleration = 9,81 [m/s²]

$F_{floor} -m*g = m*a$