Answer:
The last option, 20 N and 2.04 kg
Explanation:
work = (force)(distance)
work = 120 joules
distance: 6 m
rearrange to find force:
120=(6)F
F= 120/6 = 20 Newtons.
Assuming its lifted from Earth's surface, the force of gravity will be 9.81 m/s^2. Let's find mass:
F=mg
m=F/g
m=(20)/(9.81)= 2.038 kg
Answer:
Explanation:
Given data
Terminal velocity for spread eagle position vt=130 km/h
Terminal velocity for nosedive position vt=326 km/h
The terminal speed of the diver is given by
Therefore the area is given by
Since everything else is constant in the two dives except for the terminal velocity, the ratio between the area in the slow position to the area in the fast position is
First, find the amount of time for the dart to hit the board using this equation: t = d/v
t = 2 m/ 15 m/s = 0.133 s
Then, find the height the dart has fallen from its initial point using this equation: h = 0.5gt²
h = 0.5(9.81 m/s²)(0.133 s)² = 0.0872 m or 8.72 cm
Since the diameter of the bull's eye is only 5 cm, and you started at the same level of the top of the bull's eye, that means the maximum allowance would only be 5 cm. Since it exceeded to 8.72 cm, it means that <em>Veronica will not hit the bull's eye.</em>
Answer:
<em>The comoving distance and the proper distance scale</em>
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Explanation:
The comoving distance scale removes the effects of the expansion of the universe, which leaves us with a distance that does not change in time due to the expansion of space (since space is constantly expanding). The comoving distance and proper distance are defined to be equal at the present time; therefore, the ratio of proper distance to comoving distance now is 1. The scale factor is sometimes not equal to 1. The distance between masses in the universe may change due to other, local factors like the motion of a galaxy within a cluster. Finally, we note that the expansion of the Universe results in the proper distance changing, but the comoving distance is unchanged by an expanding universe.
