True I think is the answer
Answer:
hmmm
Explanation:
hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
The answer should be:
KOH (aq) + HCl (aq) --> KCl (aq) + H20 (l).
KOH is a base, because OH can accept a H+.
HCl is an acid because it can donate a H+.
In general, bases are : OH-, and acids are : H+.
When we can get Pka for K2HPO4 =6.86 so we can determine the Ka :
when Pka = - ㏒ Ka
6.86 = -㏒ Ka
∴Ka = 1.38 x 10^-7
by using ICE table:
H2PO4- → H+ + HPO4
initial 0.4 m 0 0
change -X +X +X
Equ (0.4-X) X X
when Ka = [H+][HPO4] / [H2PO4-]
by substitution:
1.38 X 10^-7 = X^2 / (0.4-X) by solving for X
∴X = 2.3x 10^-4
∴[H+] = X = 2.3 x 10^-4
∴PH = -㏒[H+]
= -㏒ (2.3 x 10^-4)
∴PH = 3.6
