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neonofarm [45]
3 years ago
15

What is the oxidation state of Mn atom

Chemistry
1 answer:
liraira [26]3 years ago
4 0

The oxidation state for an atom on Mn or manganese is +2. It also depends on the element it can be paired with. When it is paired with the compound KMnO4, the oxidation state of Mn is 5+. Oxidation state is useful in redox reactions.

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hydrogen-2 is also known as deuterium as well as hydrogen-3 is known as tritium hydrogen-1 is our common hydrogen isotope a samp
UkoKoshka [18]
H-1 only has 1 proton and 1 electron, so its mass number is 1.
H-2 has one more neutron so its mass number is 2
H-3 has one more neutron than H-2 so its mass number will be 3.
average atomic mass = 1 x 99% + 2 x 0.8% + 3 x 0.2%
=1.012
6 0
4 years ago
How might a molecule with two strong bond dipoles have no molecular dipole at all?
Reil [10]
 A molecule with two strong bond dipoles can have no molecular dipole if the bond dipoles cancel each other out by pointing in exactly opposite directions. For example, in carbon dioxide (a linear molecule), the carbon-oxygen bonds have a <span>large dipole moment. However, because one dipole points to the left and the other to the right the dipole is cancelled.</span>
5 0
3 years ago
Is h2so4 a Arrhenius acid
MAVERICK [17]
Answer : Yes , H2SO4 is an arrhenius acid

<h2>Explanations : </h2>

• An ,Arrhenius acid ,is a substance that ,dissociates, in water to form ,hydrogen ions (H+).

,

• In other words, an arrhenius acid increases the H+ ion concentration in aqueous solution.

,

• This can be represented by the equation :

H_SO_4^{-\text{ }}\rightleftarrows H^{+\text{ }}+SO_4^{2-}

• Therefore, H2SO4 is a strong arrhenius acid.

4 0
1 year ago
Read 2 more answers
The entire set of chemical reactions carried out by an organism make up the organism’s _____.
choli [55]

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3 0
3 years ago
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How many grams of solid NaOH are required to prepare a 400ml of a 5N solution? show your work!
Nuetrik [128]

<u>Answer:</u> The mass of solid NaOH required is 80 g

<u>Explanation:</u>

Equivalent weight is calculated by dividing the molecular weight by n factor. The equation used is:

\text{Equivalent weight}=\frac{\text{Molecular weight}}{n}

where,

n = acidity for bases = 1 (For NaOH)

Molar mass of NaOH = 40 g/mol

Putting values in above equation, we get:

\text{Equivalent weight}=\frac{40g/mol}{1eq/mol}=40g/eq

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Mathematically,

\text{Normality of solution}=\frac{\text{Number of gram equivalents} \times 1000}{\text{Volume of solution (in mL)}}

Or,

\text{Normality of solution}=\frac{\text{Given mass}\times 1000}{\text{Equivalent mass}\times \text{Volume of solution (in mL)}}         ......(1)

We are given:

Given mass of NaOH = ?

Equivalent mass of NaOH = 40 g/eq

Volume of solution = 400 mL

Normality of solution = 5 eq/L

Putting values in equation 1, we get:

5eq/L=\frac{\text{Mass of NaOH}\times 1000}{40g/eq\times 400mL}\\\\\text{Mass of NaOH}=80g

Hence, the mass of solid NaOH required is 80 g

4 0
4 years ago
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