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natulia [17]
2 years ago
12

Macy always thought there were only a few hair colors:blond,brown,and black. However,when she actually began looking around, she

saw varying shades of these hair colors. What is a possible reason for so many different hair colors
Chemistry
2 answers:
____ [38]2 years ago
7 0

Answer: The pigmentation of hairs is composed by different levels of eumelanin and pheomelanin. These pigments combined compose all the colours of hair. The more quantity of eumelanin the darker the hair is. Also, the level of the composition can vary over time, causing changes on the colour of the hair.  

Dafna1 [17]2 years ago
6 0

Answer: Pigment.

Explanation: Our hair color is determined by two types of pigment, Eumelanins, and Pheomelanins. Which together produces all the natural hair colors we see every day with other people.

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Answer:

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Which elements have fewer than four dots in their electron dot diagrams
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Which of the following will be most soluble in octane?
natima [27]

Answer:

CH3CH3CH2CH3

Explanation:

Octane is a non-polar compound. It is a hydrocarbon with 8-carbon length along its chain.

It belongs to a special group of hydrocarbons called alkanes.

What makes a substance soluble in another?

   It is a common phrase that  "like dissolves like". This is applicable to solubility of substances in another.

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7 0
3 years ago
The equilibrium 2NO(g)+Cl2(g)⇌2NOCl(g) is established at 500 K. An equilibrium mixture of the three gases has partial pressures
QveST [7]

<u>Answer:</u>

<u>For A:</u> The K_p for the given reaction is 4.0\times 10^1

<u>For B:</u> The K_c for the given reaction is 1642.

<u>Explanation:</u>

The given chemical reaction follows:

2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)

  • <u>For A:</u>

The expression of K_p for the above reaction follows:

K_p=\frac{(p_{NOCl})^2}{(p_{NO})^2\times p_{Cl_2}}

We are given:

p_{NOCl}=0.24 atm\\p_{NO}=9.10\times 10^{-2}atm=0.0910atm\\p_{Cl_2}=0.174atm

Putting values in above equation, we get:

K_p=\frac{(0.24)^2}{(0.0910)^2\times 0.174}\\\\K_p=4.0\times 10^1

Hence, the K_p for the given reaction is 4.0\times 10^1

  • <u>For B:</u>

Relation of K_p with K_c is given by the formula:

K_p=K_c(RT)^{\Delta ng}

where,

K_p = equilibrium constant in terms of partial pressure = 4.0\times 10^1

K_c = equilibrium constant in terms of concentration = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature = 500 K

\Delta ng = change in number of moles of gas particles = n_{products}-n_{reactants}=2-3=-1

Putting values in above equation, we get:

4.0\times 10^1=K_c\times (0.0821\times 500)^{-1}\\\\K_c=\frac{4.0\times 10^1}{(0.0821\times 500)^{-1})}=1642

Hence, the K_c for the given reaction is 1642.

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2 years ago
a cell on a microscope slide and noticed cell walls and cell membrane bound organelles. the students conclude the cells are what
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