The shape of a protein molecule resembles BEADS ON A STRING.
Proteins are macro molecules that are formed from amino acids. There are different types of amino acids, thus, different amino acids combine together to form different types of protein. This means that, proteins are formed from sequences of amino acids; they are long chains of different amino acids, that is why, they are likened to beads on string.
The structures of proteins are in three dimensions, they are primary, secondary and tertiary structures. The primary structure refers to the sequence of the amino acids in a protein. The amino acids in the primary structure are linked together by peptide bonds.
Answer:
hypochlorite ion
Explanation:
The hypochlorous acid, HClO, is a weak acid with Ka = 1.36x10⁻³, when this acid is in solution with its conjugate base, ClO⁻ (From sodium hypochlorite, NaClO) a buffer is produced. When a strong acid as HCl is added, the reaction that occurs is:
HCl + ClO⁻ → HClO + Cl⁻.
Where more hypochlorous acid is produced.
That means, the HCl reacts with the hypochlorite ion present in solution
I believe the answer is B??????????? Hope this helps
~Queensupreme
Answer:

Explanation:
Hello,
In this case, the described chemical reaction is:

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

Best regards.
Answer:
carbon
Explanation:
because it is an allotrope of carbon