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AlekseyPX
3 years ago
15

The magnetic field lines of a bar magnet spread out from the north end to the south end. South end to the north end. Edges to th

e center. Center to the edges.
Physics
2 answers:
Ede4ka [16]3 years ago
5 0

Answer

the answer is option A/ "north end to the south end"

Explanation:

Gwar [14]3 years ago
3 0
<h3><u>Answer;</u></h3>

the north end to the south end.

<h3><u>Explanation;</u></h3>
  • Magnetic field lines from a bar magnet form lines that are closed. The direction of magnetic field is taken to be outward from the North pole of the magnet and in to the South pole of the magnet.
  • A magnetic field refers to  the area surrounding a magnet where a force is exerted on certain objects. These lines are spread out of the north end of the magnet.
  • The magnetic field lines resemble a bubble.
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A projectile is fired with an initial velocity of 450 feet per second at an angle of 70° with the horizontal.
pav-90 [236]
<h2>After 26.28 seconds projectile returns 26.28 seconds.</h2>

Explanation:

Initial velocity = 450 ft/s = 137.16 m/s

Angle, θ = 70°

Consider the vertical motion of projectile,

When the projectile return to the ground we have

           Displacement, s = 0 m

           Acceleration, a = -9.81 m/s²

            Initial velocity, u = 137.16 x sin70 = 128.89 m/s

Substituting in s = ut + 0.5 at²

                s = ut + 0.5 at²

                0 = 128.89 x t + 0.5 x (-9.81) x t²

                t² - 26.28 t = 0

                t ( t- 26.28) = 0

               t = 0 s or t = 26.28 s

After 26.28 seconds projectile returns 26.28 seconds.

5 0
3 years ago
Learning Goal: To understand the behavior ofthe electric field at the surface of a conductor, and itsrelationship to surface cha
Ivan

Complete Question

The complete question is shown on the first uploaded image  

Answer:

a   it is always zero

b  0

c  \eta  =  -\epsilon _o E

Explanation:ss

Here the  net charge is  on the outer surface of the conductor thus this means that the net charge inside the conductor is zero

Generally the charge density of a conductor is dependent on the charge per unit area  which implies that the charge density is dependent on the net charge  so this  means that the charge density inside the conductor is zero

 

Generally the direction of electric field this from the  positive charge to the negative charge  so from the question we can deduce  that the negative charge is located on the surface of the conductor

    So We can mathematically define the charge density on the surface of the electric field as

             ∮E \cdot dA =  \frac{-Q}{\epsilon _o}

Where E is the electric field

          dA change in unit area

           -Q is the negative charge

          \epsilon _o  is the permittivity of free space

So

          EA  =  \frac{-Q}{\epsilon _o }

           \frac{Q}{A}  =  -\epsilon _o E

          \eta  =  -\epsilon _o E

Where \eta is the charge density

   

8 0
3 years ago
What equations would you use to find force?
Klio2033 [76]

Answer:

F = m x a

Explanation:

F = force

m = mass of an object

a = acceleration

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cestrela7 [59]

Answer: C

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3 0
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Propose a hypothesis for how the position of the ball will affect the amount of its gravitational pull energy
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