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Naya [18.7K]
3 years ago
8

A helicopter blade spins at exactly 110 revolutions per minute. Its tip is 4.50 m from the center of rotation. (a) Calculate th

e average speed (in m/s) of the blade tip in the helicopter's frame of reference. m/s
(b) What is its average velocity (in m/s) over one revolution? m/s
Physics
1 answer:
NeX [460]3 years ago
8 0

Answer:

(a). The average speed is 51.83 m/s.

(b). The average velocity over one revolution is zero.

Explanation:

Given that,

Angular velocity = 110 rev/m

Radius = 4.50 m

(a). We need to calculate the average speed

Using formula of average speed

v=r\omega

v = 4.50\times110\times\dfrac{2\pi}{60}

v=51.83\ m/s

(b). The average velocity over one revolution is zero because the net displacement is zero in one revolution.

Hence, (a). The average speed is 51.83 m/s.

(b). The average velocity over one revolution is zero.

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Amiraneli [1.4K]

Answer:

I believe it's A.)

Explanation:

Although light comes into our atmosphere through refraction, it reaches our eyes only through reflection from objects. So when light rays reflect off an object and enter the eyes through the cornea you can then see that object.

Hope this helps you out : )

7 0
3 years ago
Please answer fast in hindi ​
Ipatiy [6.2K]

Answer:

1. Dheere Dheere (slowly slowly)

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4. Mat (don't)

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8 0
2 years ago
Mathematically speaking, the energy of a wave is directionally proportional to the square of the amplitude of the wave Calculate
kenny6666 [7]

The energy of the wave is D) 16.0 units squared

Explanation:

The energy of a wave is directly proportional to the square of the amplitude of the wave.

Mathematically, this can be written as

E\propto A^2

where

E is the energy of the wave

A is its amplitude

For the wave in this problem, the amplitude is

A = 4 units

Therefore, assuming that the constant of proportionality is 1, the energy of this wave is

E=A^2=4^2=16 units squared

Learn more about waves:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

6 0
3 years ago
Read 2 more answers
An ac generator has a maximum emf output of 150 V. What is the rms current in the circuit when the generator is connected to a 3
natima [27]

This is an insidious question.  Quite frankly, I would not have
expected to see it here on Brainly.  But I'm ready to play the
cards that you have dealt me.

None of the choices offered is a correct solution.

If the output of the AC generator is nice and sinusoidal, and
its maximum (peak) emf is 150 volts, then its RMS emf is

                             (1/2) (150) (√2)  =  106.07 volts.

The resistor's dissipation is   

                             Power = (current) x (voltage) .

If the resistor is dissipating its full rated 35W, then

                       35W  =  (current) x (106.07 V)

Divide each side by 106.07 V:   

           RMS Current =  (35W) / (106.07 V)  =  0.33 Ampere .
_________________________________________

Looking over the choices offered . . . 

The largest choice ... 3.1 A ... is the current in a resistor
that is dissipating 35W if the voltage is

                           (35W / 3.1A)  =  11.29 volts .

The smallest choice ... 1.2 A ... is the current in a resistor
that is dissipating 35W if the voltage is

                           (35W / 1.2A)  =  29.17 volts .

Whatever you meant the so-called "150 V" of the generator
to represent ... whether the RMS sinusoidal, peak sinusoidal,
peak square-wave, RMS square-wave, DC, average, etc. ...
none of the choices for current, in combination with any of these
generators, would dissipate 35W.

3 0
3 years ago
What is the frequency of light with a wavelength of 725 nm?
Dennis_Churaev [7]
Frequency of light = speed of light/wavelength = 3x10⁸/725x10⁻⁹ =4.13 x 10¹⁴ Hz
3 0
3 years ago
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