First it will accelerate with acceleration a = 2.62 m/s^2
now the distance that it will move with this acceleration is
d1 = 0.5 * 2.62 * 12.8^2 = 214.6 m
so it will cover first 241.6 m during acceleration
now it will cover next distance with constant speed
so the distance covered is given as
d2 = v* t
d2 = 33.536 * 0.895*60 = 1800.9 m
after this it will comes to rest by constant deceleration which is given as by a = -11.2 m/s^2
so the distance it will cover is given by
d3 = (v^2 - vi^2)/(2a)
d3 = (0^2 - 33.536^2) / (2*-11.2)
d3 = 50.2 m
so the total distance that it move is given by
d = d1 + d2 + d3
d = 214.6 + 1800.9 + 50.2
d = 2065.7
so the total displacement is 2065.7 m
I guess itll be between C and D
Answer:
the maximum force will be equal to 134.84 N
Explanation:
We have given mass m = 43 kg
Coefficient of static friction
Acceleration due to gravity
We have to find the maximum force which , when applied there is no movement of crates
This maximum force will be equal to frictional force
Frictional force is given by
So the maximum force will be equal to 134.84 N
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