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4 years ago

The greenhouse effect keeps earth warmer than it would normally be. True False

Physics

1 answer:

MariettaO [177]4 years ago

6 0

Answer:

The World Is Pure Enough as it is that we don't melt or (lose air) \_/

Explanation:

All people don't have to be concerned about is a disruption of the plethora of gases we already have in our atmosphere and trees need C02 in order to breath and that's what cows produce that's what we breath out and what coal plants and fossil fuels produce the more C02 the more trees produce oxygen because trees breathe in C02 and pop out Oxygen and plus power plants don't produce C02 they produce water vapor so (ALL IN ALL C02 Will not cause the Ice Caps to melt because trees already have that issue covered that's why the scientists said they fixed the global warming issue to keep people from whining about a non-existent problem. so basically its true The greenhouse effect does keep the earth warm halfly because of the hot gases that get trapped in the atmosphere like C02.True

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Which water depth had the biggest difference in survival rates for embryos with UV-B protection versus embryos without UV-B prot

sergiy2304 [10]

Answer:

10 cm

Explanation:

water depth had the biggest difference in survival rates for embryos with UV-B protection versus embryos without UV-B protection is 10 cm . the bar graph attached in the shows that the lengths of yellow and brown bars differ the most at 10 cm.

Hence,The biggest difference between the survival rates of UV-B protected and unprotected can be seen at the depth of 10 cm.

6 0

3 years ago

A plant species has two possible gene variations for seed shape. One plant has smooth seeds, and another has wrinkled seeds. The

vovikov84 [41]

Answer: The correct answer is- The plant with the smooth seeds is homozygous for the dominant trait.

According to the Mendelian genetics, dominant trait is the one that expresses itself and masks the expression of the recessive trait. Dominant is depicted with capital letter and recessive with small letter.

Let us consider 'S' depicts the allele for smooth seed and 's' for the wrinkled seeds. There can be two genotypes for smooth seeds that is 'Ss' and 'SS' whereas only one genotype is possible for wrinkled ( 'ss') seeds.

As per the question, there is no chance of the offspring born with wrinkled seeds. This is only possible when the parental plant with smooth seeds is homozygous for the dominant trait ( like SS) . Therefore, only smooth trait will be visible in the offsprings ( with genotype Ss) of the parental plants and there will be no chance of wrinkled seeds (ss) in the offsprings.

6 0

3 years ago

Read 2 more answers

A 62-kg person jumps from a window to a fire net 20.0 m directly below, which stretches the net 1.4 m. Assume that the net behav

gayaneshka [121]

Answer:

a) x = 0.098

b) x = 2.72 m

Explanation:

(a) To find the stretch of the fire net when the same person is lying in it, you can assume that the net is like a spring with constant spring k. It is necessary to find k.

When the person is falling down he acquires a kinetic energy K, this energy is equal to the elastic potential energy of the net when it is max stretched.

Then, you have:

$K=U\\\\\frac{1}{2}mv^2=\frac{1}{2}kx^2$ (1)

m: mass of the person = 62kg

k: spring constant = ?

v: velocity of the person just when he touches the fire net = ?

x: elongation of the fire net = 1.4 m

Before the calculation of the spring constant, you calculate the final velocity of the person by using the following formula:

$v^2=v_o^2+2gy$

vo: initial velocity = 0 m/s

g: gravitational acceleration = 9.8 m/s^2

y: height from the person jumps = 20.0m

$v=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(20.0m)}=14\frac{m}{s}$

With this value you can find the spring constant k from the equation (1):

$mv^2=kx^2\\\\k=\frac{mv^2}{x^2}=\frac{(62kg)(14m/s)^2}{(1.4m)^2}=6200\frac{N}{m}$

When the person is lying on the fire net the weight of the person is equal to the elastic force of the fire net:

$W=F_e\\\\mg=kx$

you solve the last expression for x:

$x=\frac{mg}{k}=\frac{(62kg)(9.8m/s^2)}{6200N/m}=0.098m$

When the person is lying on the fire net the elongation of the fire net is 0.098m

b) To find how much would the net stretch, If the person jumps from 38 m, you first calculate the final velocity of the person again:

$v=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(38m)}=27.29\frac{m}{s}$

Next, you calculate x from the equation (1):

$x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(62kg)(27.29m/s)^2}{6200N/m}}\\\\x=2.72m$

The net fire is stretched 2.72 m

5 0

3 years ago

An electron, moving south, enters a magnetic field of certain strength. Because of this field the electron curves upward. What i

e-lub [12.9K]

Answer: The magnetic field points to the west.

Explanation:

If we take the plane as:

North = positive y-axis

East = positive x-axis.

We have that the electron is moving south, so the velocity of the electron can be written in vector form as:

V = (0, -v, 0)

Now, when the electron interacts with the magnetic field, the electron moves upwards.

We know that the interaction between an electron and a magnetic field is:

F = q*VxB

So we have that this force acts on the z-direction.

Now, to solve this we can use the righ hand rule.

First, we point wit our hand to the direction of the velocity (negative y-axis) now, we want that our thumb points up (the direction of the force) so the side where our palm faces is the direction of the field B.

But, remember that an electron has a negative charge, so the actual equation is:

F = -q*VxB

So the magnetic field actually points in the opposite direction of our palm, to the west.

Now, we can also solve it mathematically as:

F = (0, 0, f) = -q*(0, -v,0)x(a, b, c)

where B = (a, b, c) is the vector of the magnetic field.

(0, 0, f) = -q*(-v*b -0, -0 + 0, 0 -(- a*v)) = -q*(-v*b, 0, a*v)

then we have that b must be equal to zero, and that:

f = -q*a*v

and f is positive, then we have:

a = -(f/q*v)

then the vector of the magnetic field is:

B = (-(f/q*v), 0, 0)

so it points in the negative x-axis, that is the West, as we found earlier.

4 0

3 years ago

Place the following steps in order for motor control. 1. Upper motor neurons stimulate lower motor neurons. 2. Sensory informati

Alla [95]

Answer:

3, 5, 1, 4, 2

Explanation:

When the body needs to move, certain muscles need to be stimulated in order to perform a certain movement. There is a process that is followed that starts with the brain sending a signal, and ends with the movement being performed by the body.

3. This is the first step, because a pathway needs to be established before any electric impulses can be sent. Hence, the upper motor neurons in the premotor cortex need to choose a pathway (known as a motor program).

5. This is the second step, because once a pathway has been established, a signal needs to be sent down that pathway. Hence, the basal nuclei enable the thalamus to stimulate the upper motor neurons to send an electrical impulse down the pathway.

1. This is the third step, because once the upper motor neurons have been stimulated, they send an electrical impulse to stimulate the lower motor neurons.

4. This is the forth step, because once the electrical impulse reaches the lower motor neurons, they pass the impulse to a certain group of skeletal muscles, causing them to contract.

2. This is the final step, because once the skeletal muscles have contracted, the body has completed its movement. However, once the body has moved, sensory information is relayed to the cerebellum to ensure that the correct movement is made, and if it needs to be adjusted, then the whole process will start again in order to correct the movement.

4 0

3 years ago