3 years ago

The sun is made up mostly of

Physics

1 answer:

qaws [65]3 years ago

3 0

Answer:

the first one, gas

Explanation:

if its not what you looking for my b

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The drill used by most dentists today is powered by a small air-turbine that can operate at angular speeds of 350000 {\rm rpm} .

damaskus [11]

Answer:

5833.33

Explanation:

$\alpha$ = Angular acceleration

$\theta$ = Number of revolutions

$\omega_i$ = Initial angular speed = 0

t = Time taken = 2 s

Final angular speed

$\omega_f=\dfrac{350000}{60}=5833.33\ rps$

From the equation of rotational motion we have

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\dfrac{5833.33-0}{2}\\\Rightarrow \alpha=2916.665\ rev/s^2$

$\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \theta=0\times t+\dfrac{1}{2}\times 2916.665\times 2^2\\\Rightarrow \theta=5833.33\ rev$

The number of revolutions is 5833.33

6 0

3 years ago

A force vector has a magnitude of 599 newtons and points at an angle of 40.8° below the positive x axis. What is the x scalar co

ASHA 777 [7]

Answer:

$F_{x}=453.44N$

Explanation:

Given data

Force F=599 N

Angle α=40.8°

To find

x scalar component

Solution

The Scalar x component can be found by

$F_{x}=FCos\alpha \\F_{x}=599Cos(40.8)\\F_{x}=453.44N$

The Scalar y component can be found by

$F_{y}=-FSin\alpha \\F_{y}=-599Sin(40.8)\\F_{y}=-391.4N$

3 0

3 years ago

While hammering a nail, you put in 30 Joules of work. The hammer then puts out 10 J of

AfilCa [17]

Answer:

C Don't worry if you thought it was D. I almost answered that.

Explanation:

Remark

You can get this just by learning the vocabulary.

Efficiency = Work Out / Work In * 100%

Work in = 30J That's you swinging the hammer.

Work out = 10 J That's how much of the hammer's work gets to the nail.

Efficiency = (10/30)*100

Efficiency = 1/3 * 100

Efficiency = 33%

3 0

3 years ago

Read 2 more answers

The measure of how quickly an object’s velocity changes is called

blsea [12.9K]

Acceleration I’m pretty sure

5 0

4 years ago

Read 2 more answers

A car of mass 1800 kg can be just be lifted. What is the least force that the electromagnet must use to lift the car? (1 g = 10

Doss [256]

Answer:

m=1800kg

1800000g×10N/kg

18000000N force is required to life the car

8 0

3 years ago