Heat transferred by conduction in metals occurs when

As the moon revolves around the Earth, it also rotates on its axis. Why is it that the the same side of the moon is always visib

Nesterboy [21]

The moon dosent revolve around earth as the earth rotates the moon stays in the same place

7 0

3 years ago

Assume that a vaulter is able to carry a vaulting pole while running as fast

rewona [7]

A,walls
Speleleelelelekeke

8 0

3 years ago

Read 2 more answers

A box of mass m1 = 20.0 kg is released from rest at a warehouse loading dock and slides down a 3.0 m-high frictionless chute to

Harrizon [31]

´To develop this problem we will use the concepts related to the conservation of momentum and the application of energy conservation equations to find the velocity of the mass after the collision, like this:

Velocity of the mass $m_1$ just before the collision

$v_1 = \sqrt{2gh}$

$v_1 = \sqrt{2(9.8)(3)}$

$v_1 = 7.67m/s$

Therefore the momentum just before collision would be

$p_2 = m_1v_1+40(0)\\p_1 = 20*7.67+40(0)\\p_1 = 153.36kg \cdot m/s$

Momentum after the collision

$p_1 = 20*u_1+40u_1\\p_1 = 60u_1$

Since the momentum is conserved we have that

$153.36= 60u_1$

$u_1 = \frac{153.36}{60}$

$u_1 = 2.56m/s$

The velocity of mass $m_2$ after the collision is given by

$v_2 = \frac{2m_1}{m_1+m_2} u_1$

$v_2 = \frac{2(20)}{20+40}(2.56)$

$v_2 = 1.71m/s$

Therefore the change in momentum of mass 2 is

$p_2 = m_2v_2$

$p_2 = 40*1.71$

$p_2 = 68.4kg\cdot m/s$

Therefore the impulse acting on m2 during the collision between the two boxes is $p = 68.4kg\cdot m/s$

8 0

4 years ago

Two cars collide inelastically and stick together after the collision. Before the collision, the magnitudes of their momenta are

dolphi86 [110]

Answer:

a) P1+P2

Explanation:

The magnitude of their combined momentum is just the addition of each momentum, because in this case of inelastic collision, the kinetic energy of the two cars are both converted to some form of energy because the velocity of both cars becomes zero, i.e., V=0, making P = mv = 0, this means the magnitude of P1 + P2 = 0.

3 0

3 years ago

4 A car horn has a frequency of 400 Hz. The car is moving away from an

NeTakaya

Answer:

f = 409.6 Hz, the woman hears a higher frequency sound

Explanation:

This is a Doppler effect problem, which is described by the equation for the case of a fixed observer

f = fo $\frac{v}{v \pm v_s}$

where the negative sign is for the source approaching the observer

in this case the car is the one that emits the sound and moves away from the intersection

let's calculate

f = 400 $\frac{343}{343-8}$

f = 409.6 Hz

therefore the woman hears a higher frequency sound

7 0

3 years ago