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3 years ago

Which healthcare professional is typically a secondary care provider?

Physics

2 answers:

Keith_Richards [23]3 years ago

7 0

Answer:

Explanation:

Google.

lidiya [134]3 years ago

3 0

D)ophthalmologist
[Secondary care simply means being taken care of by someone who has particular expertise in whatever problem a patient is having.]

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Light intensity is?

Fittoniya [83]

The correct answer is:
The rate at which a waves energy flows through a given unit of area

In fact, light intensity is defined as the light power per unit of area:
 $I= \frac{P}{A}$
but the power is the energy carried by the light per unit of time:
 $P= \frac{E}{t}$
this means that the intensity can be rewritten as
 $I= \frac{E}{tA}$ 
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Does light have to have a medium to pass through?

skad [1K]

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2 years ago

An engineer is designing a runway. She knows that a plane, starting at rest, needs to reach a speed of 180mph at take-off. If th

kvv77 [185]

Answer:

The plane would need to travel at least $8,\!580\; {\rm ft}$ ( $8.58 \times 10^{3}\; {\rm ft}$ .)

The $10,\!000\; {\rm ft}$ runway should be sufficient.

Explanation:

Convert unit of the the take-off velocity of this plane to $\rm ft\cdot s^{-1}$ :

$\begin{aligned}v &= 180\; {\rm mph} \\ &= 180\; {\rm mi \cdot hrs^{-1}} \times \frac{1\; {\rm hrs}}{3600\; {\rm s}} \times \frac{5280\; {\rm ft}}{1\; {\rm mi}} \\ &= 264\; {\rm ft \cdot s^{-1}}\end{aligned}$ .

Initial velocity of the plane: $u = 0\; {\rm ft \cdot s^{-1}}$ .

Take-off velocity of the plane $v =264\; {\rm ft\cdot s^{-1}}$ .

Let $x$ denote the distance that the plane travelled along the runway. Since acceleration is constant but unknown, make use of the SUVAT equation $x = ((u + v) / 2) \, t$ .

Notice that this equation does not require the value of acceleration. Rather, this equation make use of the fact that the distance travelled (under constant acceleration) is equal to duration $t$ times average velocity $(u + v) / 2$ .

The distance that the plane need to cover would be:

$\begin{aligned}x &= \left(\frac{u + v}{2}\right)\, t \\ &= \frac{0\; {\rm ft \cdot s^{-1}} + 264\; {\rm ft \cdot s^{-1}}}{2} \times 65.0\; {\rm s} \\ &= 8.58\times 10^{3}\; {\rm ft}\end{aligned}$ .

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3 years ago

A car travels a distance of 98 meters in 10 seconds. What is the average speed of the car?

stira [4]

Answer:

Explanation:

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