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____ [38]
3 years ago
12

What is the oxidation state of cl in hclo4?

Chemistry
2 answers:
MrRissso [65]3 years ago
7 0

Answer:

+6 is the oxidation state

Irina-Kira [14]3 years ago
3 0
There is 1 H atom: (1)(+1) = +1 The oxidation number of O is -2. There are 4 O atoms here: (4)(-2) = -8 So the oxidation state of Cl is +7.

NOTE: The maximum positive oxidation number for chlorine is +7,<span> the same as its group number (VII).</span>
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What is it called when moon is between setting and rising
miv72 [106K]

Answer:

I hope this link helps you.

Explanation:

http://astronomy.swin.edu.au/cosmos/P/Phases

4 0
3 years ago
HELP FAST 100 PTSCalculate the amount of heat needed to convert 100.0 g of liquid water at 25 °C to water at 100 °C.
Alex Ar [27]

Answer:

31,380 Joules

Explanation:

Given Data:

Mass = m = 100 g

Temperature 1 = = 25 °C

Temperature 2 = = 100 °C

Specific Heat Constant = c = 4.184

Change in Temp. = ΔT = 100 - 25 = 75 °C

Required:

Heat = Q = ?

Formula:

Q = mcΔT

Solution:

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Hope this helped!

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4 0
3 years ago
Read 2 more answers
How do you determine how many neutrons an element has?
Alexandra [31]

Answer:

To find the number of neutrons, subtract the number of protons from the mass number. number of neutrons

Explanation:

4 0
3 years ago
3 The volume of a gas is 50.0 mL at 20.0 K. What will be the new
Damm [24]

Answer:

C. 4.00 K

Explanation:

We can solve this using Charles's Law of the ideal gas. The law describes that when the pressure is constant, the volume will be directly proportional to the temperature. Note that the temperature here should only use the Kelvin unit. Before compressed, the volume of the gas is 50ml(V1) and the temperature is 20K (T1). After compressed the volume becomes 10ml(V2). The calculation will be:

V1 / T1= V2 / T2

50ml / 20K = 10ml / T2

T2= 10ml/ 50ml * 20K

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7 0
3 years ago
Calculate the amount (in grams) of kcl present in 75.0 ml of 2.10 m kcl
Lera25 [3.4K]
V = 75 mL = 0,075 L = 0,075 dm³
C = 2.1M
n = ?
---------------
C = n/V
n = C×V
n = 2.1×0,075
n = 0,1575 mol
--------
mKCl: 39+35.5 = 74,5 g/mol

74,5g --------- 1 mol
Xg ------------- 0,1575 mol
X = 74,5×0,1575
X = 11,73375g KCl

:•)
5 0
3 years ago
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