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2 years ago

Which rule is used for writing the name of an ionic base?

Chemistry

2 answers:

IgorLugansk [536]2 years ago

4 0

Answer:

The chemical name ends with “hydroxide.”

Explanation:

1- we write the name of the metal first and after that write the nonmetal:

Ex : NaOH ( sodium hydroxide)

2- any compound contains OH group is an ionic base and this group called hydroxide group

3- "Ous" ending is given in the ions with the lower oxidation.

4- " ic" ending is given in the ions with the higher oxidation.

<em>So, the correct answer is: The chemical name ends with “hydroxide.”.</em>

jeka57 [31]2 years ago

3 0

Answer:

The chemical name ends with “hydroxide

Explanation:

got right on edge 2020

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Give one example of fast erosion and one example of slow erosion. Use complete sentences.

topjm [15]

An example of erosion is the Grand Canyon, which was worn away over time by the Colorado river.

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3 years ago

Read 2 more answers

What is the overall enthalpy of reaction for the equation shown below?

Rudiy27

Answer:

ΔH₁₂ = -867.2 Kj

Explanation:

Find enthalpy for 3H₂ + O₃ => 3H₂O given ...

2H₂ + O₂ => 2H₂O ΔH₁ = -483.6 Kj

3O₂ => 2O₃ ΔH₂ = + 284.6 Kj

_____________________________

3(2H₂ + O₂ => 2H₂O) => 6H₂ + 3O₂ => 6H₂O (multiply by 3 to cancel O₂)

6H₂ + 3O₂ => 6H₂O ΔH₁ = 3(-483.6 Kj) = -1450.6Kj

2O₃ => 3O₂ ΔH₂ = -284.6Kj (reverse rxn to cancel O₂)

_______________________________

6H₂ + 2O₃ => 6H₂O ΔH₁₂ = -1735.2 Kj (Net Reaction - not reduced)

________________________________

divide by 2 => target equation (Net Reaction - reduced)

3H₂ + O₃ => 3H₂O ΔH₁₂ = (-1735.2/2) Kj = -867.2 Kj

4 0

2 years ago

A runner wants to run 11.7 km. Her running pace is 8.0 mi/hr. How many minutes must she run?

ArbitrLikvidat [17]

Answer:

8 mi = 12.875 km

12.875 /60 m

= 0.21458 km / min

11.7 / 0.21458 = 54.52 min

5 0

2 years ago

I NEED HELP PLEASE, THANKS! :)

krok68 [10]

Answer:

$\large \boxed{\text{2.20 g Pb}}$

Explanation:

They gave us the masses of two reactants and asked us to determine the mass of the product.

This looks like a limiting reactant problem.

1. Assemble the information

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 239.27 32.00 207.2

2PbS + 3O₂ ⟶ 2Pb + 2SO₃

m/g: 2.54 1.88

2. Calculate the moles of each reactant

$\text{Moles of PbS} = \text{2.54 g PbS } \times \dfrac{\text{1 mol PbS}}{\text{239.27 g PbS}} = \text{0.010 62 mol PbS}\\\\\text{Moles of O}_{2} = \text{1.88 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.058 75 mol O}_{2}$

3. Calculate the moles of Pb from each reactant

$\textbf{From PbS:}\\\text{Moles of Pb} = \text{0.010 62 mol PbS} \times \dfrac{\text{2 mol Pb}}{\text{2 mol PbS}} = \text{0.010 62 mol Pb}\\\\\textbf{From O}_{2}:\\\text{Moles of Pb} =\text{0.058 75 mol O}_{2} \times \dfrac{\text{2 mol Pb}}{\text{3 mol O}_{2}}= \text{0.039 17 mol Pb}\\\\\text{PbS is the $\textbf{limiting reactant}$ because it gives fewer moles of Pb}$

4. Calculate the mass of Pb

$\text{ Mass of Pb} = \text{0.010 62 mol Pb} \times \dfrac{\text{207.2 g Pb}}{\text{1 mol Pb}} = \textbf{2.20 g Pb}\\\\\text{The reaction produces $\large \boxed{\textbf{2.20 g Pb}}$}$

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2 years ago

On the fahrenheit scale, at what temperature does water boil? a. 451°f b. 264°f c. 212°f d. 100°f

taurus [48]

The temperature that water boils on the fahrenheit scale is c. 212°f.

<h3>What is Temperature conversation?</h3>

Temperature conversation is a way of converting a temperature from a unit to another using conversation scale.

Therefore, on fahrenheit scale water boils at 212°f which is equivalent to 100°C on the Celcius scale.

Learn more about Temperature conversation at;brainly.com/question/23419049

#SPJ4

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1 year ago