Answer:
glycerol, pyruvate, glycerol -3-phosphate, dihydroxyacetone phosphate and glucose♡ hope this helps♡
Answer:
Yes they woll react.
Explanation:
Ferous oxide and zinc will be product.
7.4x10^23 = molecules of silver nitrate sample
6.022x10^23 number of molecules per mole (Avogadro's number)
Divide molecules of AgNO3 by # of molecules per mol
7.4/6.022 = 1.229 mols AgNO3 (Sig Figs would put this at 1.3)
(I leave off the x10^23 because they both will divide out)
Use your periodic table to find the molar weight of silver nitrate.
107.868(Ag) + 14(N) + 3(16[O]) = 169.868g/mol AgNO3
Now multiply your moles of AgNO3 with your molar weight of AgNO3
1.229mol x 169.868g/mol = 208.767g AgNO3
Explanation:
Formula to calculate standard electrode potential is as follows.
= 0.535 - 1.065
= - 0.53 V
Also, it is known that relation between 
and K is as follows.
ln K = 
Substituting the given values into the above formula as follows.
ln K =
= 
ln K = -41.28
K = 
= 
Thus, we can conclude that the value of the equilibrium constant for the given reaction is .
Answer is: adding NaCl will lower the freezing point of a solution.
A solution (in this example solution of sodium chloride) freezes at a lower temperature than does the pure solvent (deionized water).
The higher the solute concentration (sodium chloride), freezing point depression of the solution will be greater.
Equation describing the change in freezing point:
ΔT = Kf · b · i.
ΔT - temperature change from pure solvent to solution.
Kf - the molal freezing point depression constant.
b - molality (moles of solute per kilogram of solvent).
i - Van’t Hoff Factor.
Dissociation of sodium chloride in water: NaCl(aq) → Na⁺(aq) + Cl⁻(aq).
