Answer:
Solution that is 0.100 M CH3COOH (acetic acid)
and 0.100 M NaCH3COO (sodium acetate)
Find pH of buffer solution:
CH3COOH(aq) + H2O ↔ CH3COO-
(aq) + H3O+(aq)
[CH3COOH] [CH3COO-
] [H3O+]
initial 0.100 0.100 ≈0
-x x x
equil 0.100 – x 0.100 + x xFind pH of buffer solution:
CH3COOH(aq) + H2O ↔ CH3COO-
(aq) + H3O+(aq)
Ka = [CH3COO-
][H3O+
]
[CH 3COOH] = (.100 + x)x
(.100 - x) = 1.8 x 10-5
x = 1.80 x 10-5 M
pH = 4.7
Explanation:
Answer:
%Sgr = 1% (1 sig.fig.)
Explanation:
mass water = 350ml x 0.975g/ml = 341.25g
mass sugar added = 4g
solution mass = 341.25g + 4g = 345.25g
%sugar = (4g/345.25g)·100% = 1.1586% ≅ 1% (1 sig.fig)
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