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2 years ago

14

factors that affect the rate of a chemical reaction include which of the following? i. frequency of collisions of reactant parti

cles ii. kinetic energy of collisions of reactant particles iii. orientation of reactant particles during collisions

1 answer:

pickupchik [31]2 years ago

7 0

I, ii is the answer

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Given the chemical reaction Na2CO3 + AgNO3 , will a precipitate be formed?

stepladder [879]

A precipitate will be formed through the double displacement method in chemical reactions. The chemical equation would be:
Na2CO3 + AgNO3 ----> NaNO3 + Ag2CO3.
Balancing would result to:
<span>Na2CO3 + 2AgNO3 ----> 2NaNO3 (aq)+ Ag2CO3.
</span>
Ag2CO3 is the precipitate formed. It is yellow in color but due to the presence of elemental silver, it is a bit grayish.

3 0

3 years ago

How did Ernest Rutherford change the atomic model?

nadya68 [22]

Answer:

D. He showed that most of an atom's mass was located in the atom's

nucleus.

Explanation:

Ernest Rutherford changed the atomic model because of his experiment which was the gold foil experiment. A beam of alpha particles was aimed at a piece of gold foil, most particles passed through but some were scattered backward which showed that the middle of an atom (nucleus) is the where most of the mass is located.

6 0

3 years ago

10 m3 of carbon dioxide is originally at a temperature of 50 °C and pressure of 10 kPa. Determine the new density and volume of

Dimas [21]

Answer : The new density and new volume of carbon dioxide gas is 0.2281 g/L and $7.2m^3$ respectively.

Explanation :

First we have to calculate the new or final volume of carbon dioxide gas.

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 10 kPa

$P_2$ = final pressure of gas = 15 kPa

$V_1$ = initial volume of gas = $10m^3$

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $50^oC=273+50=323K$

$T_2$ = final temperature of gas = $75^oC=273+75=348K$

Now put all the given values in the above equation, we get:

$\frac{10kPa\times 10m^3}{323K}=\frac{15kPa\times V_2}{348K}$

$V_2=7.2m^3$

The new volume of carbon dioxide gas is $7.2m^3$

Now we have to calculate the new density of carbon dioxide gas.

$PV=nRT\\\\PV=\frac{m}{M}RT\\\\P=\frac{m}{V}\frac{RT}{M}\\\\P=\rho \frac{RT}{M}\\\\\rho=\frac{PM}{RT}$

Formula for new density will be:

$\rho_2=\frac{P_2M}{RT_2}$

where,

$P_2$ = new pressure of gas = 15 kPa

$T_2$ = new temperature of gas = $75^oC=273+75=348K$

M = molar mass of carbon dioxide gas = 44 g/mole

R = gas constant = 8.314 L.kPa/mol.K

$\rho$ = new density

Now put all the given values in the above equation, we get:

$\rho_2=\frac{(15kPa)\times (44g/mole)}{(8.314L.kPa/mol.K)\times (348K)}$

$\rho_2=0.2281g/L$

The new density of carbon dioxide gas is 0.2281 g/L

5 0

3 years ago

Luden [163]

Answer: Monoprotic Acid

6 0

3 years ago

The atomic weight of Ga is 69.72 amu. There are only two naturally occurring isotopes of gallium:

irga5000 [103]

Answer:

71 Ga has a naturally abundance of 36%

Explanation:

Step 1: Given data

Gallium has 2 naturally occurring isotopes: this means the abundance of the 2 isotopes together is 100 %. The atomic weight of Ga is 69.72 amu. This is the average of all the isotopes.

Since the average mass of 69.72 is closer to the mass of 69 Ga, this means 69 Ga will be more present than 71 Ga

Percentage 69 Ga> Percentage 71 Ga

<u>Step 2:</u> Calculate the abundance %

⇒Percentage of 71 Ga = X %

⇒Percentage of 69 Ga = 100 % - X %

The mass balance equation will be:

100*69.72 = x * 71 + (100 - x)*69

6972 = 71x + 6900 -69x

72 = 2x

x = 36 %

71 Ga has a naturally abundance of 36%

69 Ga has a naturally abundance of 64%

3 0

4 years ago