Many free radicals combine to form molecules that do not contain any unpaired electrons. The driving force for the radical–radic
al combination reaction is the formation of a new electron‑pair bond. Consider the formation of hydrogen peroxide. 2OH(g)⟶H2O2(g) Write Lewis formulas for the reactant and product species in the chemical equation. Include nonbonding electrons.
1 answer:
Answer:
In the attached image the Lewis equation is shown where it is shown how two oxygens react with two hydrogens to meet the octet of the electrons.
Explanation:
Hydrogen peroxide is one of the most named chemicals since it is not only sold as "hydrogen peroxide" in pharmacies but it is also one of the great weapons of immune defense cells to defend ourselves against anaerobic bacteria.
The disadvantage of this compound is that when dividing it forms free oxygen radicals that are considered toxic or aging for our body.
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Phosgene on reacting with <span>phenylmagnesium bromide generates benzoyl chloride.
Since, </span>phenylmagnesium bromide is added in excess. It would further react with benzoyl chloride to form benzophenone.
Benzophenone on further reacting with phenylmagnesium bromide, and aqueous treatment, gives triphenylmethanol.
Entire reaction pathways is shown below:
Since, </span>phenylmagnesium bromide is added in excess. It would further react with benzoyl chloride to form benzophenone.
Benzophenone on further reacting with phenylmagnesium bromide, and aqueous treatment, gives triphenylmethanol.
Entire reaction pathways is shown below:
We know that to relate solutions of with the factors of molarity and volume, we can use the equation: 
**NOTE: The volume as indicated in this question is defined in L, not mL, so that conversion must be made. However it is 1000 mL = 1 L.
So now we can assign values to these variables. Let us say that the 18 M
is the left side of the equation. Then we have:
We can then solve for
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and 
or 
We now know that the total amount of volume of the 4.35 M solution will be 210 mL. This is assuming that the entirety of the 50 mL of 18 M is used and the rest (160 mL) of water is then added.
**NOTE: The volume as indicated in this question is defined in L, not mL, so that conversion must be made. However it is 1000 mL = 1 L.
So now we can assign values to these variables. Let us say that the 18 M
We can then solve for
We now know that the total amount of volume of the 4.35 M solution will be 210 mL. This is assuming that the entirety of the 50 mL of 18 M is used and the rest (160 mL) of water is then added.