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Blizzard [7]
3 years ago
7

Which type of reaction has will give brainliest to first correct answer

Chemistry
2 answers:
k0ka [10]3 years ago
7 0

Answer:

I think it's replacement because the B and D just swap places in the end equation

ohaa [14]3 years ago
3 0

Answer:

D.

Explanation:

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A gaseous substance turns into a solid. Which best describes this change? A substance that has a specific shape changes to a sub
Snezhnost [94]

A substance that has no specific volume changes to a substance that has a specific volume.

8 0
4 years ago
Read 2 more answers
A sample of hydrogen gas has an initial pressure of 2.86 atm and an initial volume of 8472 mL If the volume of the
Oliga [24]
<h3>Answer:</h3>

Gas law : Boyle's law

New pressure: 66.24 atm

<h3>Explanation:</h3>

Concept tested: Gas laws (Boyle's law)

<u>We are given,</u>

  • Initial pressure, P₁ = 2.86 atm
  • Initial volume, V₁ = 8472 mL
  • New volume, V₂ IS 365.8 mL

We need to determine the new pressure, P₂

  • According to Boyle's law , the volume of a fixed mass of a gas and the pressure are inversely proportional at constant temperature.
  • That is, P\alpha \frac{1}{V}
  • This means , PV = k (constant)
  • Therefore; P₁V₁ = P₂V₂
  • Rearranging the formula, we can get the new pressure, P₂

P₂ = P₁V₁ ÷ V₂

   = (2.86 atm × 8472 mL) ÷ 365.8 mL

   = 66.24 atm

Therefore, the new pressure is 66.24 atm

5 0
3 years ago
How much energy is lost to condense 300. grams of steam at 100.C?
True [87]

Energy lost to condense = 803.4 kJ

<h3>Further explanation</h3>

Condensation of steam through 2 stages:

1. phase change(steam to water)

2. cool down(100 to 0 C)

1. phase change(condensation)

Lv==latent heat of vaporization for water=2260 J/g

\tt Q=300\times 2260=678000~J

2. cool down

c=specific heat for water=4.18 J/g C

\tt Q=300\times 4.18\times (100-0)=125400

Total heat =

\tt 678000+125400=803400~J

3 0
3 years ago
Can someone answer this?
yulyashka [42]

No se si aun necesitas ayuda o no

3 0
2 years ago
What is the % composition of Carbon in Chromium (iii) Carbonate
photoshop1234 [79]

Step 1 - Discovering the ionic formula of Chromium (III) Carbonate

Chromium (III) Carbonate is formed by the ionic bonding between Chromium (III) (Cr(3+)) and Carbonate (CO3(2-)):

Cr^{3+}+CO^{2-}_3\rightarrow Cr_2(CO_3)_3

Step 2 - Finding the molar mass of the substance

To find the molar mass, we need to multiply the molar mass of each element by the number of times it appears in the formula of the substance and, finally, sum it all up.

The molar masses are 12 g/mol for C; 16 g/mol for O and 52 g/mol for Cr. We have thus:

\begin{gathered} C\rightarrow3\times12=36 \\  \\ O\rightarrow9\times16=144 \\  \\ Cr\rightarrow2\times52=104 \end{gathered}

The molar mass will be thus:

M=36+104+144=284\text{ g/mol}

Step 3 - Finding the percent composition of carbon

As we saw in the previous step, the molar mass of Cr2(CO3)3 is 284 g/mol. From this molar mass, 36 g/mol come from C. We can set the following proportion:

\begin{gathered} 284\text{ g/mol ---- 100\%} \\ 36\text{ g/mol ----- x} \\  \\ x=\frac{36\times100}{284}=\frac{3600}{284}=12.7\text{ \%} \end{gathered}

The percent composition of Carbon is thus 12.7 %.

8 0
1 year ago
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