aqueous lithium hydroxide solution is used to purify air (remove co2) in spacecrafts and submarines. the pressure of carbon diox
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Answer:
3.38%
Explanation:
Given that;
the mass of the whole milk sample = 100 g
volume of HCl = 100 mL = 0.1 L
molarity of HCl = 0.5 M
volume of NaOH = 34.50 mL = 0.0345 L
molarity of NaOH = 0.3512 M
Since we knew the molarity and volume of both HCl and NaOH; we can calculate their corresponding number of moles present.
So, number of moles of HCl = molarity of HCl × volume of HCl
number of moles of HCl = 0.5 M × 0.100 mL
= 0.05 mole
number of moles of NaOH = Molarity of NaOH × Volume of NaOH
number of moles of NaOH = 0.3512 M × 0.0345 L
= 0.012 mole
From the question, we can deduce that the number of HCl that is consumed by NH₃ is equal to the number of moles of HCl that is consumed by NaOH.
SO, number of moles of HCl consumed by NH₃ = Total moles of HCl - moles of HCl consumed by NaOH
= 0.05 mole - 0.012 mole
= 0.038 mole
However, to determine the mole of NH₃ present , we have:
number of moles of NH₃ present = number of moles of HCl consumed by NH₃ = 0.038
∴ the mass of Nitrogen with the molecular weight (14.0 g/mol) = 0.038 moles × 14.0 g/mol
= 0.530 g
Now, the percentage of Nitrogen can be calculated as;
%
the percentage of protein in the sample = CP × %age of N
where CP is given as 6.38
∴ the percentage of protein in the sample = 6.38 × 0.530%
the percentage of protein in the sample = 3.3814%
the percentage of protein in the sample = 3.38%
Answer : The mass of silver chlorate will be 2.654 grams.
Explanation :
The balanced chemical reaction is,
First we have to calculate the moles of oxygen gas at STP.
As, 22.4 L volume of oxygen gas present in 1 mole of oxygen gas
So, 0.466 L volume of oxygen gas present in mole of oxygen gas
Now we have to calculate the moles of silver chlorate.
From the balanced chemical reaction, we conclude that
As, 3 moles of oxygen produced from 2 moles of silver chlorate
So, 0.0208 moles of oxygen produced from moles of silver chlorate
Now we have to calculate the mass of silver chlorate.
Molar mass of silver chlorate = 191.32 g/mole
Therefore, the mass of silver chlorate will be 2.654 grams.