Question

aqueous lithium hydroxide solution is used to purify air (remove co2) in spacecrafts and submarines. the pressure of carbon dioxide in a cabin having a volume of 2.4 x105 l is 7.9 x 10-3 atm at 39oc. eventually the pressure of co2 is reduced to 1.2 x 10-4 atm. how many grams of water are formed by this process? the ideal gas law and stoichiometry chp. 5.5 2lioh(aq) co2(g) à li2co3(aq) h2o(l)

Answer 1

The mass of the water is 1580 g.

What is the amount of water formed?

We know that the ideal gas equation can be used to obtain the number of moles of the gas. We have been told that the pressure of the gas reduced from  7.9 x 10-3 atm to  1.2 x 10-4 atm. The change in pressure can be used obtain the number of moles.

Change in pressure = 7.9 x 10-3 - 1.2 x 10-4 = 7.78 * 10^-3 atm

Using;

PV = nRT

n = PV/RT

n = 7.78 * 10^-3 atm *  2.4 x10^5 l/0.082 * (39 + 273)

n = 85 moles

Since 1 mole of carbon dioxide produces 1 mole of water

85 moles of carbon dioxide produces 85 mole of water

Mass of water produced = 85 mole  * 18 g/mol

= 1580 g

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