81.9 % is the percent yield of reaction of zinc with iodine producing ZnI2.
Explanation:
Balanced chemical equation for the reaction:
Zn + I2 ⇒ ZnI2
Data given:
mass of sample zinc = 129 grams
mass of ZnI2 formed = 510.6 grams (actual yield)
number of moles = 
number of moles of zinc = 
= 1.97 moles
from stoichiometry
1 mole of Zn reacts to form 1 mole of ZnI2
1.97 moles of Zn will form 1.97 moles of ZnI2
atomic mass of ZnI2 = 319.22 grams/mole
mass of ZnI2 formed = 628.86 grams (theoretical yield)
% yield =
x100 equation 1
from the reaction,
Putting the values in equation 1
% yield =
x 100
= 81.19 % is the % yield.
I'd say true.
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Lets say you put random stuff in a box. That stuff is matter, filling the box.
Its common to say that matter is everything around you. You can see everything around you (almost).
There are approximately 6.02 × 10²³ atoms of phosphorus in one mole of 30.974 grams of phosphorus (option A).
<h3>How to calculate number of atoms?</h3>
The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number. That is;
no of atoms = no of moles × 6.02 × 10²³
According to this question, there are 30.974 grams of phosphorus in one mole of phosphorus. The number of atoms can be calculated as follows:
no of moles of P = 30.974g ÷ 31g/mol = 0.99mol
number of atoms = 0.99 mol × 6.02 × 10²³
number of atoms = 6.02 × 10²³ atoms
Therefore, there are approximately 6.02 × 10²³ atoms of phosphorus in one mole of 30.974 grams of phosphorus.
Learn more about number of atoms at: brainly.com/question/8834373
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