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3241004551 [841]
2 years ago
11

How do you convert kilograms to pounds?

Chemistry
1 answer:
Maru [420]2 years ago
4 0

Answer:  (1 Kilogram = 2.20462 pounds) . There are 2.2046226218 lb in 1 kilogram. To convert kilograms to pounds, multiply your figure by 2.205 for an approximate result. 1 kilogram is also equal to 2 lb and 3.27396195 oz. Working out a rough estimate in your head for converting to pounds and ounces may be tricky - remember that there are 16 ounces in a pound.

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What occurs when a coordinate covalent bond is formed between nitrogen and hydrogen in the ammonium ion, NH4+?
NeX [460]
Covalent bonds are formed when electrons are shared between elements that are nonmetals. The ammonium ion, NH+4 , would have covalent bonds because both nitrogen and hydrogen are nonmetals. ... So, the bond between this particular hydrogen atom and the central nitrogen is a dative covalent bond.
4 0
2 years ago
Complete combustion of 2.0 metric tons of coal to gaseous carbon dioxide releases 6.6X10¹⁰ J of heat. Convert this energy to
Jobisdone [24]

6.6 × 10^{10} J = 6.2 × 10^{7} British thermal units

First of all, we should know that 1 British thermal unit = 1055 Joules.

From question, heat = 6.6 × 10^{10} J

1 BTU = 1055 J

6.6 × 10^{10} J = \frac{1}{1055} ×  6.6 × 10^{10} British thermal units

                   = 6.2 × 10^{7} British thermal units

1000 Joules = 1 kilojoule

A kilojoule is a unit of measure of energy, in the equal way that kilometers degree distance. meals energy used to be measured in energy  and some international locations still use those gadgets.

The power we get from foods and drinks is measured in kilojoules. that is the metric time period for calorie. Kilojoules and energy constitute the equal aspect. One calorie is ready four kilojoules.

Calorie a unit for measuring warmth same to the quantity of warmth required to elevate the temperature of one gram of water one diploma Celsius.

Learn more about kilojoules here :- brainly.com/question/490326

#SPJ4

4 0
1 year ago
The standard enthalpy of formation for glucose [c6h12o6(s)] is −1273.3 kj/mol. what is the correct formation equation correspond
balu736 [363]
The standard formation equation for glucose C6H12O6(s) that corresponds to the standard enthalpy of formation or enthalpy change ΔH°f = -1273.3 kJ/mol is 
     C(s) + H2(g) + O2(g) → C6H12O6(s)
and the balanced chemical equation is 
     6C(s) + 6H2(g) + 3O2(g) → C6H12O6(s)

Using the equation for the standard enthalpy change of formation 
     ΔHoreaction = ∑ΔHof(products)−∑ΔHof(Reactants)
     ΔHoreaction = ΔHfo[C6H12O6(s)] - {ΔHfo[C(s, graphite) + ΔHfo[H2(g)] + ΔHfo[O2(g)]}

C(s), H2(g), and O2(g) each have a standard enthalpy of formation equal to 0 since they are in their most stable forms:
     ΔHoreaction = [1*-1273.3] - [(6*0) + (6*0) + (3*0)]
                           = -1273.3 - (0 + 0 + 0)
                           = -1273.3
8 0
3 years ago
Dating of Rock Layers
Sati [7]

Answer:

I'm sorry, we need the image to answer  it.

Explanation:

4 0
2 years ago
The percent composition of nh42c2o4
zzz [600]

Answer: Percent composition by element

Element Symbol Mass Percent

Hydrogen H 6.498%

Carbon C 19.357%

Nitrogen N 22.574%

Oxygen O 51.571%

HOPE THIS HELPS

5 0
2 years ago
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