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3241004551 [841]
2 years ago
11

How do you convert kilograms to pounds?

Chemistry
1 answer:
Maru [420]2 years ago
4 0

Answer:  (1 Kilogram = 2.20462 pounds) . There are 2.2046226218 lb in 1 kilogram. To convert kilograms to pounds, multiply your figure by 2.205 for an approximate result. 1 kilogram is also equal to 2 lb and 3.27396195 oz. Working out a rough estimate in your head for converting to pounds and ounces may be tricky - remember that there are 16 ounces in a pound.

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Match each number to how it would appear in scientific notation.
Verdich [7]
A. 8,330 --> 8.33 × 10^3
B. 83.3 --> 8.33 × 10^1
C. 0.00833 --> 8.33 × 10^-3
D. 0.0833 --> 8.33 × 10^-2
E. 83,330 --> 8.33 × 10^4

Hope this helps!
4 0
3 years ago
Read 2 more answers
1. The gases SO2, O2 and SO3 are allowed to reach equilibrium at a constant temperature. The equilibrium constant for the reacti
irina [24]

Answer:

a)

K_2=1.3x10^{2}atm^{-1/2}

b)

PCl_5\rightarrow PCl_3+Cl_2

[PCl_5]=0.0375M

Explanation:

Hello!

a) In this case, since we can see that the second reaction is equal to the half of the first reaction, we can relate the equilibrium constants as shown below:

K_2=K_1^{1/2}

Thus, by plugging in the the equilibrium constant of the first reaction we obtain:

K_2=(1.6x10^4atm^{-1})^{1/2}\\\\K_2=1.3x10^{2}atm^{-1/2}

b) In this case, for the described reaction we can write:

PCl_5\rightarrow PCl_3+Cl_2

Thus, the corresponding equilibrium expression is:

K=\frac{[PCl_3][Cl_2]}{[PCl_5]}

In such a way, since we know the equilibrium constant and the concentrations of PCl3 and Cl2 at equilibrium, we can compute the concentration of PCl5 at equilibrium as follows:

[PCl_5]=\frac{[PCl_3][Cl_2]}{K}\\

[PCl_5]=\frac{\frac{0.20mol}{4L} *\frac{0.12mol}{4L} }{0.04}

[PCl_5]=0.0375M

Best regards!

7 0
2 years ago
What happens when an atom has more electrons than can fit in one energy
Verizon [17]

Answer: A. The extra electrons start to fill higher sublevels in the energy level.

Explanation:

8 0
2 years ago
A 20.0 mL sample of a NaCl solution has a mass of 21.040g. After the solution is evaporated to dryness, the dry salt residue has
Vilka [71]
Mass NaCl = 4.348
Mass solution = 21.040 - 4.348 = 16.692
mass/mass % =
4.348/16.692
= 26%
mass/vol % =
21.7%
Molecular mass of NaCl = 58.5
Moles of NaCl = 0.074
Volume of solution = 0.02 L
Molarity = 3.7 mol/Liter
7 0
3 years ago
Every pure substance has exact and specific density. What are two purposes that a chemist would use a calculated density for.
adell [148]

Answer:

1. Density can be used to identify a substance

2. Density can be used to ascertain whether a substance will float in water.

Explanation:

The calculation of the density of a substance can be used to identify the substance. If the density of a substance is calculated accurately, and compared with a table of standard densities, then we can identify that substance.

Also, density determines whether an object will float or sink in water. If an object is less dense than water then it will float in water. If it is denser than water, then it will sink in water.

7 0
3 years ago
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