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3241004551 [841]
3 years ago
11

How do you convert kilograms to pounds?

Chemistry
1 answer:
Maru [420]3 years ago
4 0

Answer:  (1 Kilogram = 2.20462 pounds) . There are 2.2046226218 lb in 1 kilogram. To convert kilograms to pounds, multiply your figure by 2.205 for an approximate result. 1 kilogram is also equal to 2 lb and 3.27396195 oz. Working out a rough estimate in your head for converting to pounds and ounces may be tricky - remember that there are 16 ounces in a pound.

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How are characteristic properties of matter used to it different matter? ​
Lisa [10]

Answer:

You can tell types of matter apart based on their properties. Physical properties of matter can be observed or measured without changing the identity of the substance.... Characteristic physical properties are properties that are always the same for a substance - so they can be used to identify a substance.

Explanation:

5 0
3 years ago
Which statement best describes balancing equations and the law of conservation of mass?
Marta_Voda [28]

Answer:

B.) The number of atoms is the same in the reactants and in the products, and the total mass is the same in the reactants and in the products.

Explanation:

law of conservation of matter/mass states that no atoms can be created or destroyed

hope this helps :)

6 0
3 years ago
The components of a mixture maintain their original properties. T/F
Georgia [21]
The components of a mixture maintain their original properties. True. That is because a mixture is not combined chemically. 
6 0
3 years ago
2. What is the mass of 5.3 moles of CaCl2?
Tanya [424]

Answer:

590 g CaCl₂

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

5.3 mol CaCl₂

<u>Step 2: Identify Conversions</u>

Molar Mass of Ca - 40.08 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of CaCl₂ - 40.08 + 2(35.45) = 110.98 g/mol

<u>Step 3: Convert</u>

<u />5.3 \ mol \ CaCl_2(\frac{110.98 \ g \ CaCl_2}{1 \ mol \ CaCl_2} ) = 588.194 g CaCl₂

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules and round.</em>

588.194 g CaCl₂ ≈ 590 g CaCl₂

5 0
3 years ago
How do you calculate the volume of a gas at STP given the number of moles of gas present
S_A_V [24]
The Ideal Gas Law states that pressure (P) × volume (V) is equal to the # of moles (n) of the gas × a constant (R) × temperature (T), such that the equation is:
PV = nRT
At standard temp and pressure (STP), the T is 0°C or 273.15K, the P is 1 atm or 760 torr, and the R constant is 0.0821. Therefore the equation, solved for V becomes: V = nRT/P, or V = n(0.0821)(273)/1, so that it reduces to V = 22.4 Liters, when n = 1 mole.
So the V of any gas at STP is 22.4 L / mole
8 0
4 years ago
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