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LuckyWell [14K]
3 years ago
12

A metal wire is in thermal contact with two heat reservoirs at both of its ends. Reservoir 1 is at a temperature of 686 K, and r

eservoir 2 is at a temperature of 292 K. Compute the total change in entropy arising from the conduction of 1216 J of heat through the wire. Please give your answer in units of J/K.
Physics
1 answer:
steposvetlana [31]3 years ago
7 0

Answer:

ΔS = 3.09 J/K

Explanation:

Entropy is defined as the magnitude of disorder in a system. Mathematically, entropy change is given as, the heat absorbed or released by a system divided by the change in absolute temperature. So, the formula for entropy change is as follows:

ΔS = ΔQ/ΔT

where,

ΔS = Change in Entropy of Metal Wire = ?

ΔQ = Heat Conducted through Wire = 1216 J

ΔT = Difference in Temperature = 686 K - 292 K = 394 K

Therefore,

ΔS = 1216 J/394 K

<u>ΔS = 3.09 J/K</u>

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Further Explanation:

The electric field intensity at a point is the measure of the force exerted by a charge particle on another charge particle in the particular area of its strength.

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Answer Details:

Grade: Senior school

Subject: Physics

Chapter: Electrostatics

Keywords:  Strength, electric field, charge, distance, electric field intensity, magnitude of charge, electrostatic, test charge, kq/r^2.

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Answer:

Explanation:

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Determine the moment of the force at AAA about point PPP. Use a vector analysis and express the result in Cartesian vector form.
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Answer:

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Explanation:

At the moment it is defined

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Let's apply this expression to the exercise

a) P = (-6 i ^ -3j ^ -6 k ^) m

       F = (-6 i ^ -3j ^ -6k ^) 103 N

       τ =\left[\begin{array}{ccc}i&j&k\\-6&-3&-6\\-6&-3&-6\end{array}\right]  

       τ = i ^ (3 6 - 3 6) + j ^ (6 6 -6 6) + k ^ (6 3 - 3 6)

        τ = 0

b) P = 24i ^ + 8j ^ + 9k ^

     F = 24i + 8j + 9k

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c) P = -6i + 6j-4k

      F = -6i + 6j-4k

      τ = i ^ (24-24) + j ^ (- 24 + 24) + k ^ (-36 + 36)

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Let's change the sign of strength

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   Tae = (I j k 24 -8 9 -24 8 -9)

   Tae = i ^ (72 -72) + j ^ (- 216 + 216) + k ^ (192-192)

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Random errors can result from the instrument not being precise or from mistakes by the researcher.

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