1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nadusha1986 [10]
3 years ago
14

Two particles, one with charge −7.97×10−6 C and the other with charge 6.91×10−6 C, are 0.0359 m apart. What is the magnitude of

the force that one particle exerts on the other?
Physics
1 answer:
kolbaska11 [484]3 years ago
7 0

Answer:

-384.22N

Explanation:

From Coulomb's law;

F= Kq1q2/r^2

Where;

K= constant of Coulomb's law = 9 ×10^9 Nm^2C-2

q1 and q2 = magnitudes of the both charges

r= distance of separation

F= 9 ×10^9 × −7.97×10^−6 × 6.91×10^−6/(0.0359)^2

F= -495.65 × 10^-3/ 1.29 × 10^-3

F= -384.22N

You might be interested in
How can using a combination of environmental policy tools be beneficial?
Ne4ueva [31]
Using a combination of environmental  policy tools can be beneficial because it is renewable source that us humans can use repeatedly. Also, if you think about it in terms of the Earth we live in we burn fossil fuels, so that limits or reduces the amount of gas we are burning out and produces clean air for plants and humans to live in.
8 0
3 years ago
Read 2 more answers
Please explain what is couloms law?
svp [43]

Answer:

Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the separation distance between the two objects.

Explanation:

4 0
3 years ago
in the history of astronomy, which of the following is true? a. galileo galilei was a student of tycho brahe. b. johannes kepler
bija089 [108]
C. Ptolemy argued that earth was the center of the universe
7 0
3 years ago
If an object accelerating at −1.5m/s^2 takes 1.2s to reach 5.0m/s, what was its initial speed?
USPshnik [31]

-1.5 m/s^2 x 1.2 seconds = -1.8 m/s

It is a negative value which means the object slowed down. The object would have originally been going that amount more.


5.0 + 1.8 = 6.8 m/s


answer: 6.8 m/s

3 0
2 years ago
What is its maximum altitude above the ground? The answer is the maximum height above the ground
Kisachek [45]

Answer:

Maximum altitude above the ground = 1,540,224 m = 1540.2 km

Explanation:

Using the equations of motion

u = initial velocity of the projectile = 5.5 km/s = 5500 m/s

v = final velocity of the projectile at maximum height reached = 0 m/s

g = acceleration due to gravity = (GM/R²) (from the gravitational law)

g = (6.674 × 10⁻¹¹ × 5.97 × 10²⁴)/(6370000²)

g = -9.82 m/s² (minus because of the direction in which it is directed)

y = vertical distance covered by the projectile = ?

v² = u² + 2gy

0² = 5500² + 2(-9.82)(y)

19.64y = 5500²

y = 1,540,224 m = 1540.2 km

Hope this Helps!!!

3 0
4 years ago
Other questions:
  • Where is relative time recorded
    7·1 answer
  • Volume of sound is controlled by the _____ of a wave
    10·1 answer
  • Describe in short the working system of a water pump ​
    12·1 answer
  • What is most often given a value of zero to describe an object position on a srtaight line
    9·1 answer
  • What happens to a light ray if it is incident on a reflective surface along the normal?
    8·1 answer
  • To understand Newton's 1st law. Newton's Principia states this first law of motion: An object subject to no net force maintains
    5·1 answer
  • Someone pls help! My physics quiz is today:(
    11·2 answers
  • A bulb is rated as 25Watt -250 Volt. On connecting this bulb to a mains of 250 volts, what will be the value of current (I) flow
    5·1 answer
  • How much force would you need to accelerate a 4 kg object from a standstill to 5 m/s2?
    5·1 answer
  • a 1200 kg car rolling on a horizontal surfact has a speed of 25 m/s when it strikes a horizontal coiled spring and is brought ot
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!