All categories

3 years ago

Charged atom or particle

Chemistry

2 answers:

GenaCL600 [577]3 years ago

7 0

Answer:

for what

Explanation:

jek_recluse [69]3 years ago

6 0

It’s charged atom I believe

You might be interested in

Which element is in the same family as Chlorine (Cl) and Fluorine (F)?

ValentinkaMS [17]

Answer/Explanation:

Chlorine and Fluorine are in the Halogen family. The elements in the Halogen family are:

Fluorine (F)

Chlorine (Cl)

Bromine (Br)

Iodine (I)

Astatine (At)

Tennessine (Ts)

Hydrogen (H) is a nonmetal

Oxygen (O) is a nonmetal

Lithium (Li) is an alkaline metal.

8 0

3 years ago

Read 2 more answers

A parent who is convinced that children have rights that ought not to be interfered with by adults is most likely:

DedPeter [7]

(does this belong in chemistry?)

anyways, the parent was most likely a kid who wanted privacy. they wanted something so they are giving it to their kids.

7 0

3 years ago

Which planets mass is nearly double that of mercury?

Nana76 [90]

Answer:

earth I think like that because earth is the second planet

4 0

2 years ago

Th e molar absorption coeffi cient of a substance dissolved in water is known to be 855 dm3 mol−1 cm−1 at 270 nm. To determine t

Olegator [25]

Answer : The percentage reduction in intensity is 79.80 %

Explanation :

Using Beer-Lambert's law :

$A=\epsilon \times C\times l$

$A=\log \frac{I_o}{I}$

$\log \frac{I_o}{I}=\epsilon \times C\times l$

where,

A = absorbance of solution

C = concentration of solution = $3.25mmol.dm^{3-}=3.25\times 10^{-3}mol.dm^{-3}$

l = path length = 2.5 mm = 0.25 cm

$I_o$ = incident light

$I$ = transmitted light

$\epsilon$ = molar absorptivity coefficient = $855dm^3mol^{-1}cm^{-1}$

Now put all the given values in the above formula, we get:

$\log \frac{I_o}{I}=(855dm^3mol^{-1}cm^{-1})\times (3.25\times 10^{-3}mol.dm^{-3})\times (0.25cm)$

$\log \frac{I_o}{I}=0.6947$

$\frac{I_o}{I}=10^{0.6947}=4.951$

If we consider $I_o$ = 100

then, $I=\frac{100}{4.951}=20.198$

Here 'I' intensity of transmitted light = 20.198

Thus, the intensity of absorbed light $I_A$ = 100 - 20.198 = 79.80

Now we have to calculate the percentage reduction in intensity.

$\% \text{reduction in intensity}=\frac{I_A}{I_o}\times 100$

$\% \text{reduction in intensity}=\frac{79.80}{100}\times 100=79.80\%$

Therefore, the percentage reduction in intensity is 79.80 %

3 0

3 years ago

What type of bonding is found in the compound of2?

Ratling [72]

Answer:

chemical bond

Explanation:

because atom can join together by forming a chemical bond

7 0

3 years ago