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ivann1987 [24]
3 years ago
12

Charged atom or particle

Chemistry
2 answers:
GenaCL600 [577]3 years ago
7 0

Answer:

for what

Explanation:

jek_recluse [69]3 years ago
6 0
It’s charged atom I believe
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A certain mass of carbon reacts with 9.53 g of oxygen to form carbon monoxide. ________ grams of oxygen would react with that sa
yawa3891 [41]

Answer: 9.53 *2= 19.06

Explanation:

The law of multiple proportions states that if two elements combines to form more than one compound the ratio of masses of the second element which combines to the fixed mass of the first element will always be the ratios of the small whole numbers.

in case of carbon monoxide, mass of carbon will be the same of mass of oxygen.

But in case of carbon dioxide, if carbon is 9.53 units then oxygen will be twice as that of carbon.

CO2, so 9.53*2= 19.06 grams of oxygen will combine with 9.53 grams of carbon to form carbon dioxide.

3 0
3 years ago
In a pendulum, a continuous change occurs between kinetic energy and
Masja [62]
It should be potential energy!!!
7 0
3 years ago
In printed form, the Oxford English Dictionary __________________.
inna [77]
Will i thank <span>consists of many volumes
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3 0
3 years ago
Calculate the solubility of benzene in water at 25 c in ppm. the required henry's law constant is 5.6 bar/mol/kg and benzene's s
kap26 [50]

The relationship between pressure and solubility of the gas is given by Henry's law as:

S_g = kP_g

where,

S_g is the solubility of the gas.

k is proportionality constant i.e. Henry's constant.

P_g is pressure of the gas.

k = 5.6 bar/mol/kg (given)

P_g = 0.13 bar (given)

Substituting the values,

S_g = 5.6 bar/mol/kg\times 0.13 bar = 0.728 mole/kg

To convert mole/kg to g/kg:

Molar mass of benzene, C_6H_6 = 6\times 12+6\times 1 = 78 g/mol

0.728\times 78 = 56.784 g/kg

Now for converting into ppm:

Since, 1 ppm = 0.001 g/kg

So, 56.784\times 1000 = 56784 ppm.

Hence, the solubility of benzene in water at 25^{o} C in ppm is 56784 ppm.


7 0
3 years ago
Two closed vessels contain chlorine gas at the same conditions of temperature and
wariber [46]

Answer:12 mol

Explanation: both vessels are at the same temp and pressure (and the pressure is low and/or the temperature high).

6.7mol per 1.3L = 6.7/1.3 mol/L

so in 2.33L = 6.7*2.33/1.3 = 12 mol

8 0
3 years ago
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