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balandron [24]
3 years ago
12

What are three possible blood type alleles?

Chemistry
2 answers:
Keith_Richards [23]3 years ago
8 0

Answer:

Three possible blood type alleles are Iᴬ, Iᴮ and i

Explanation:

Iᴬ, Iᴮ and i are three possible blood type alleles.

Iᴬ and Iᴮ are known as co-dominant, and The i allele is recessive.

Thus, Three possible blood type alleles are Iᴬ, Iᴮ and i

<u>-TheUnknownScientist</u>

artcher [175]3 years ago
3 0
There are three different alleles, known as IA, IB, and i. The IA and IB. The possible human phenotypes for blood group are type A, type B, type AB, and type O. Three or more alternative forms of a gene (alleles) that can occupy the same locus. However, only two of the alleles can be present in a single organism.
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g in the combustion of 0.398 mol c4h8, how many moles of o2 would be required to completely react with the fuel?
storchak [24]

41.4 grams of oxygen is essentially required for complete combustion of 3 moles of butane gas.

<h3>What is combustion?</h3>
  • Combustion is a chemical reaction that often involves the presence of oxygen and produces heat and light in the form of flames.
  • Because of the nature of the chemical reaction and the fact that more energy is produced than can be released into the surrounding medium, the rate or speed at which the reactants combine is high.
  • As a result, the temperature of the reactants is increased, accelerating the process even further.

As you know, combustion reaction is a chemical reaction in which a substance reacts with the atmospheric oxygen (O₂) to produce carbon dioxide and water. Therefore, balanced combustion reaction of butane (C₄H₁₀) will be as follows:

C₄H₁₀+\frac{13}{2}O₂→4CO₂+5H₂O

You can observe in the above reaction that, \frac{13}{2} moles of oxygen are required for combustion of 1 mole of butane.

Therefore, going by unitary method, for complete combustion of 3 moles of butane, (\frac{13}{2}×0.398) moles of oxygen would be required.

Now, we know, number of moles = \frac{Given mass}{Molar mass}

Molar mass of oxygen is 16 g/mol

We need to find a given mass which is the mass of oxygen required when the number of moles is equal to 2.59.

Thus, given mass of oxygen or mass of oxygen required = number of moles of oxygen × molar mass of oxygen

Mass of oxygen required = 2.59 moles × 16 g/mol = 41.4 g.

Hence, 41.4 grams of oxygen is essentially required for complete combustion of 3 moles of butane gas.

To learn more about combustion, refer to

brainly.com/question/13251946

#SPJ4

8 0
1 year ago
1. the smallest complete unit of a compound or diatomic gas shell
kogti [31]

Answer:

Explanation:

1. The smallest complete unit of a compound or diatomic gas

ATOM

Atoms are small tiny particles that makes up a molecule. It is regarded as the smallest indivisible particle that parts in a chemical reaction.

2. A new substance formed by the combination of two or more different atoms

COMPOUNDS

Compounds are substances composed of two or more kinds of atoms. Their properties differs from those of the constituent elements that combines to make them up.

3. Path of electrons around an atomic nucleus

SHELL

The shell describes the path of an electron round a nucleus

4. A substance consisting of only one type of atom

MONOATOMIC MOLECULE

It is an aggregate of one type of atom.

5 0
3 years ago
The light traveled from _____________________ to __________________. (What transparent materials?)
sergiy2304 [10]

Explanation:

High density medium to low density medium.

5 0
2 years ago
Roland is measuring a physical property of an object. He records the measurement:
Vsevolod [243]

Answer:

The correct answer is density. See the explanation below, please.

Explanation:

Roland measured density, which is a property that relates mass to volume, having units for example: grams / cm3

3 0
3 years ago
Mendeleev organized the elements:
pashok25 [27]

Answer: (3)

Medeleev arranged elements in order of increasing atomic weight and similar properties

He noticed that similar elements were grouped together by using this.

4 0
3 years ago
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