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balandron [24]
3 years ago
12

What are three possible blood type alleles?

Chemistry
2 answers:
Keith_Richards [23]3 years ago
8 0

Answer:

Three possible blood type alleles are Iᴬ, Iᴮ and i

Explanation:

Iᴬ, Iᴮ and i are three possible blood type alleles.

Iᴬ and Iᴮ are known as co-dominant, and The i allele is recessive.

Thus, Three possible blood type alleles are Iᴬ, Iᴮ and i

<u>-TheUnknownScientist</u>

artcher [175]3 years ago
3 0
There are three different alleles, known as IA, IB, and i. The IA and IB. The possible human phenotypes for blood group are type A, type B, type AB, and type O. Three or more alternative forms of a gene (alleles) that can occupy the same locus. However, only two of the alleles can be present in a single organism.
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The immune system responds to antigens by producing cells that directly attack the pathogen, or by producing special proteins called antibodies. Antibodies attach to an antigen and attract cells that will engulf and destroy the pathogen. The main cells of the immune system are lymphocytes known as B cells and T cells.

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1362205.2 in scientific notation
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Zinc phosphide, Zn3P2, is often used as a rat poison. Phosphorus has 5 valence electrons. How many valence electrons does each z
Helen [10]
The choices that should have accompanied this question were:
A. 1 
<span>B. 2 </span>
<span>C. 3 </span>
<span>D. 4 
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My answer is B. 2.
Below is an explanation, I found while doing the research.

<span>Phosphate needs 3 electrons each totaling 6 electrons so each zinc will need to give up 2 electrons.

Phosphate wants to imitate the electron configuration of Argon because noble configurations are the most stable. With P getting the extra electrons the valence shell will be 3s2 3p6, which is the same as Argon. Without the extra electrons, the P valence shell looks like this 3s2 3p3, now you can see why each phosphorus wants 3 more electrons, that will make it 3s2 3p6, just like Argon.</span>
8 0
3 years ago
Read 2 more answers
You wish to make a 0.375 M hydroiodic acid solution from a stock solution of 6.00 M hydroiodic acid. How much concentrated acid
cluponka [151]

We need to add 2.09 mL of concentrated acid to obtain 75 mL of 0.335 M HBr solution.

You are performing a dilution of HBr going from a concentration of 12M to 0.335M, and you want to end up with a final volume of 75 ml of the dilute solution.

Consider the dilution formula: M1V1 = M2V2.

The basis behind this formula is that the number of moles of the acid before and after the dilution must remain constant.

M1 = the molarity of the stock solution,

M2 = the molarity of the diluted solution,

V2 = the final volume of the diluted solution.

In this case, we need to determine V1, which is the volume of the stock solution used to prepare the diluted sample. With this knowledge, we can plug our numbers into the equation and we obtain the following:

(12 mol/L)*V1 = (0.335mol/L)*(0.075L).

Keeping in mind that molarity is the moles of a substance in one liter of solution, we will use mol/L instead of M. By doing this, we are reminded that in order to use this equation, we must convert 75 mL into units of liters.

After rearranging the equation and solving for V1, we find that V1 = 0.00209L.

Finally, we must convert back from liters to mL by multiplying the final answer by 1000.

This way we end up with V1 = 2.09 mL.

This means that we need to add 2.09 mL of concentrated acid to obtain 75 mL of 0.335 M HBr solution.

Learn more about molarity here: brainly.com/question/23243759

#SPJ4

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Un bioquímico para preparar una solución disuelve 50 gramos de droga en 150 gramos de agua. Calcular:
aleksandrvk [35]

Answer:b

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