Since liquid CO2 cannot exist at pressures lower than 5.11 atm, the triple point is defined as 56.6 °C and 5.11 atm.
Are CO2 liquids explosive?
Although it can impair judgement at high doses, carbon dioxide is neither poisonous nor combustible. Asphyxiation is typically seen as the primary risk associated with CO2. The Boiling Liquid Expanding Vapour Explosion, however, is a serious risk connected to compressed CO2 (BLEVE)
What PSI does CO2 turn into liquid at?
Only at pressures more than 5.1 atm does liquid carbon dioxide form; the triple point of carbon dioxide is approximately 518 kPa at 56.6 °C. Depending on the pressure, the liquid's boiling point ranges from -70°F to +88°F. The expansion ratio when vaporised at 60°F is 535:1. CO2 is a gas or liquid.
Toknw more about Liquid CO2 visit:
https://brainly.in/question/16890479
#SPJ4
The periodic table of elements arranges all of the known chemical elements in an informative array. Elements are arranged from left to right and top to bottom in order of increasing atomic number. Order generally coincides with increasing atomic mass. The rows are called periods.
Avogadro's number is defined as the number of elementary particles (molecules, atoms, compounds, etc.) per mole of a substance. It is equal to 6.022×1023 mol-1 and is expressed as the symbol NA.
Answer:
0.0277 M.
Explanation:
The integral rate law of a first order reaction:
<em>Kt = ln ([A₀]/[A]),</em>
where, k is the rate constant of the reaction <em>(k = 3.36 × 10⁻⁵ s⁻¹)</em>,
t is the time of the reaction <em>(t = 235.0 min = 14100 s)</em>,
[A₀] is the initial concentration of cyclopropane <em>([A₀] = 0.0445 M)</em>
<em>∵ Kt = ln ([A₀]/[A]),</em>
∴ (3.36 × 10⁻⁵ s⁻¹)(14100 s) = ln (0.0445 M)/[A]
Taking the exponential of both sides:
1.6 = (0.0445 M)/[A]
<em>∴ [A] = (0.0445 M)/1.6 = 0.0277 M.</em>
<em />
Generally speaking, organic molecules tend to dissolve in solvents that have similar physical properties. A good rule of thumb is that "like dissolves like". Meaning, polar compounds can dissolve polar compounds and nonpolar compounds can dissolve nonpolar compounds.
To apply this to the current problem, we are told that the brushes are being cleaned with vegetable oil or mineral oil. In this case, the oils are used as solvents. In order for these solvents to be effective, the compounds they are trying to dissolve must be similar in structure and properties to other oils. Therefore, vegetable oil or mineral oil will be most effective in removing oil-based paints, as these will have the similar properties needed to dissolve in the oil solvents.
