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uranmaximum [27]
3 years ago
14

Earth's Revolution question:

Chemistry
1 answer:
Murljashka [212]3 years ago
7 0

Answer:

itos6oyoyoydkgzkstgjuf

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How many parents are needed to produce a baby tiger?
marysya [2.9K]

Answer:

Only 2

Explanation:

3 0
3 years ago
If you have 3 moles of a gas at a pressure of 2.5 atm and a volume of 8 liters, what is the temperature?
fomenos

Answer:

d

Explanation:

pv=nrt

2.5×1.01×10^5×8×10^-3=3×8.31×T

T=

3 0
3 years ago
Read 2 more answers
Which of the following happens during a lunar eclipse?
Svetlanka [38]

Answer:

a. Earth casts a shadow on the moon.    

Explanation:

Lunar eclipse occurs when Earth comes in between sun and moon. The sunlight falling on moon is blocked by Earth and the shadow of earth falls on moon. This happens on full moon day when sun, earth and moon align in one line.The moon passes through the shadow of earth and appears dark.

Thus, the correct option is a.

5 0
3 years ago
How is the number of unpaired valance electrons in an atom related to the number of bonds that the atom can form?
TiliK225 [7]
It is the same amount. For example, Carbon has 4 electrons. Putting those 4 electrons in a Lewis Dot Structure will show that they are not paired, so 4 is the number of bonds Carbon can make.
6 0
3 years ago
Phosphorite is a mineral that contains plus other non-phosphorus-containing compounds. What is the maximum amount of that can be
8_murik_8 [283]

Phosphorus can be prepared from calcium phosphate by the following reaction:

2Ca_3(PO_4)_2(s)+6SiO_2(s)+10C(s)\rightarrow 6CaSiO_3(s)+P_4(s)+ 10CO(g)

Phosphorite is a mineral that contains Ca_3(PO_4)_2 plus other non-phosphorus-containing compounds. What is the maximum amount of P_4 that can be produced from 2.3 kg of phosphorite if the phorphorite sample is 75% Ca_3(PO_4)_2 by mass? Assume an excess of the other reactants.

Answer: Thus the maximum amount of P_4 that can be produced is 0.345 kg

Explanation:

Given mass of phosphorite Ca_3(PO_4)_2  = 2.3 kg

As given percentage of phosphorite Ca_3(PO_4)_2 is = \frac{75}{100}\times 2.3kg=1.725kg=1725g

moles=\frac{\text {given mass}}{\text {Molar mass}}

{\text {moles of}Ca_3(PO_4)_2=\frac{1725g}{310g/mol}=5.56moles

2Ca_3(PO_4)_2(s)+6SiO_2(s)+10C(s)\rightarrow 6CaSiO_3(s)+P_4(s)+ 10CO(g)

According to stoichiometry:

2 moles of phosphorite gives = 1 mole of P_4

Thus 5.56 moles of phosphorite give= \frac{1}{2}\times 5.56=2.78moles of P_4

Mass of P_4=moles\times {\text {Molar mass}}=2.78mol\times 124g/mol=345g=0.345kg

Thus the maximum amount of P_4 that can be produced is 0.345 kg

5 0
3 years ago
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