Answer:
T2 = 29°C
Explanation:
Given data:
Heat added = 420 j
Mass of water = 25 g
Initial temperature = 25°C
Final temperature = ?
Solution;
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water = 4.18 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Now we will put the values.
420 j = 25 g ×4.18 j/g.°C × (Final temperature - initial temperature)
420 j = 25 g ×4.18 j/g.°C × (T2 - 25°C)
420 j = 104.5 j/°C × (T2 - 25°C)
420 j /104.5 j/°C = T2 - 25°C
4°C + 25°C = T2
T2 = 29°C
Answer:
B
Explanation:
I know im right I forgot some of the lessons cause this was still in grade 3 now Im grade 6....
There are three types of
wind load or wind forces.
<span>Uplift load is the first one;
this is when the wind flow pressures create a strong lifting effect. Wind flow under the roof pushes upward, while
wind flow over the roof goes upward.</span>
Answer:
70 amu
Explanation:
The average atomic mass of an element is calculated by first finding the products of the atomic masses of the isotopes of that element and their respective percent abundances. The second/last step is finding the sum of those products, applying significant figures rules throughout. In this case, you would do the following:
(69 x 60%) + (71 x 40%) = 70 amu (with significant figures rules applied)
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