Using the equation PV = nRT
Therefore; V = nRT / P
Need moles of glucose converted to moles of the product gas (CO2).
Molecular weight calculation:
C 6 X 12.01 = 72.06
H 12 X 1.01= 12.12
O 6 X 16.00 = 96.00
sum = 180.18
25.5 g of C6H12O6 ( 1 mol C6H12O6 / 180.18 g) ( 6 mol CO2 / 1 mol C6H12O6) =
0.84915 mol CO2 gas.
Convert temp: 37 °C + 273.15 = 310.15 K
V= ((0.84915 mol)× (0.0821 L atm / mol K) (310.15 K))/0.980 atm
V = 22.0635 L
= 22.06 L CO2
Answer:
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Answer:
Rate of reaction = 2.0 M/s
Explanation:
2H2O2(g) --> 2H2O(g) + O2(g)
Rate of formation of H2O = 2.0 M/s
Rate of reaction can be measured using multiple techiques and parameters like volume, pressure etc.
Among these techniques is the measurement of appearance of products.
This means we have;
Rate of reaction = Rate of appearance of product
Hence;
Rate of reaction = 2.0 M/s
Answer:
The chemical reactions in which oxidation and reduction takes place are called redox reaction.
Explanation:
CH4. + O2----> CO2. + H2O
