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Katarina [22]
3 years ago
7

A certain metal alloy is composed of 10% tin, 16% antimony, and 74% lead. If you were to have 500 g of the alloy, how many grams

of antimony would be found in this sample?
a. 370g
b.50g
c.80g
d. 16g
Chemistry
1 answer:
kenny6666 [7]3 years ago
3 0

Answer:

c. 80 g

Explanation:

metal alloy:

  • wt% = (mass compound/mass alloy)×100

for antimony:

⇒ 16% = (g antimony / g alloy)×100

⇒ 0.16 = g antimony / g alloy

∴ g alloy = 500 g

⇒ (0.16)×(500 g) = g antimony

⇒ g antimony = 80 g

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How many liters of 15.0 molar NaOH stock solution will be needed to make 17.5 liters of a 1.4 molar NaOH solution? Show the work
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The dilution factor essentially tells you how concentrated the stock solution was compared with the diluted solution.

In your case, the dilution must take you from a concentrated hydrochloric acid solution of 18.5 M to a diluted solution of 1.5 M, so the dilution factor must be equal to

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In this case, you're working with very concentrated hydrochloric acid, so it would be best to keep the stock solution and the water needed for the dilution in an ice bath before the dilution.

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Always remember

Water to concentrated acid →.NO!

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