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Katarina [22]
3 years ago
7

A certain metal alloy is composed of 10% tin, 16% antimony, and 74% lead. If you were to have 500 g of the alloy, how many grams

of antimony would be found in this sample?
a. 370g
b.50g
c.80g
d. 16g
Chemistry
1 answer:
kenny6666 [7]3 years ago
3 0

Answer:

c. 80 g

Explanation:

metal alloy:

  • wt% = (mass compound/mass alloy)×100

for antimony:

⇒ 16% = (g antimony / g alloy)×100

⇒ 0.16 = g antimony / g alloy

∴ g alloy = 500 g

⇒ (0.16)×(500 g) = g antimony

⇒ g antimony = 80 g

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As we know,

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Law of multiple proportion states that when two elements combine with each other to form more than one compounds , the mass of one element with respect to the fixed mass of another element are in ratio of small whole numbers.

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Answer:

1. 3.57\times 10^{-4}was the K_a value calculated by the student.

2. 5.93\times 10^{-4}was the K_b of ethylamine value calculated by the student.

Explanation:

1.

The pH value of Aspirin solution = 2.62

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Volume of the solution = 0.600 L

The initial concentration of Aspirin  = c = \frac{0.01111 mol}{0.600 L}=0.0185 M

HAs\rightleftharpoons As^-+H^+

initially

c       0    0

At equilibrium

(c-x)      x   x

The expression of dissociation constant :

K_a=\frac{[As^-][H^+]}{[HAs]}:

K_a=\frac{x\times x }{(c-x)}

=\frac{0.00240 M\times 0.00240 M}{(0.0185-0.00240 )}

K_a=3.57\times 10^{-4}

3.57\times 10^{-4}was the K_a value calculated by the student.

2.

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K_b=\frac{[C_2H_5NH_3^{+}][OH^-]}{[C_2H_5NH_2]}:

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K_b=5.93\times 10^{-4}

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3 years ago
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