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3 years ago

HELP ASAP! GIVING BRAINLIEST!! Why would a pendulum stop swinging? Where did the energy go?

Chemistry

2 answers:

kvasek [131]3 years ago

7 0

Answer:

The pendulum would stop swinging because the kinetic energy would slow down for the friction is causing it to slow. The energy would go into potential energy.

galina1969 [7]3 years ago

7 0

Answer:

friction/heat

Explanation:

the pendulum would eventually stop swinging dude to friction in the air. the friction makes heat even if it is the smallest amount it is still energy. the pendulum would eventually stop due to friction which makes heat

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Liquids have a(n)____shape and A(n)_____volume.

shusha [124]

B. Indefinite, definite

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3 years ago

What is the empirical formula for the compound P4O6??

777dan777 [17]

The empirical formula is P₂O₃

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3 years ago

Calculate the mass of calcium chloride that contains 3.20 x 1024 atoms of chlorine.

frez [133]

Answer:

294.87 gm CaCl_2

Explanation:

The computation of the mass of calcium chloride is shown below:

But before that following calculations need to be done

Number of moles of chlorine atom is

= 3.20 × 10^24 ÷ 6.022 × 10^23

= 5.314 moles

As we know that

1 mole CaCl_2 have the 2 moles of chlorine atoms

Now 5.341 mole chloride atoms would be

= 1 ÷ 2 × 5.314

= 2.657 moles

Now

Mass of CaCl_2 = Number of moles × molar mass of CaCl_2

= 2.657 moles × 110.98 g/mol

= 294.87 gm CaCl_2

7 0

3 years ago

Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 500.

patriot [66]

Explanation:

Chemical reaction equation for the give decomposition of $NH_{3}$ is as follows:.

$2NH_{3}(g) \rightleftharpoons N_{2}(g) + 3H_{2}(g)$

And, initially only $NH_{3}$ is present.

The given data is as follows.

$P_{NH_{3}}$ = 2.3 atm at equilibrium

$P_{H_{2}} = 3 \times P_{N_{2}}$ = 0.69 atm

Therefore,

$P_{N_{2}} = \frac{0.69 atm}{3}$

= 0.23 aatm

So, $P_{NH_{3}}$ = 2.3 - 2(0.23)

= 1.84 atm

Now, expression for $K_{p}$ will be as follows.

$K_{p} = \frac{(P_{N_{2}})(P^{3}_{H_{2}})}{(P^{2}_{NH_{3}})}$

$K_{p} = \frac{(0.23) \times (0.69)^{3}}{(1.84)^{2}}$

= $\frac{0.23 \times 0.33}{3.39}$

= 0.0224

or, $K_{p} = 2.2 \times 10^{-2}$

Thus, we can conclude that the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture is $2.2 \times 10^{-2}$ .

6 0

3 years ago

Chemist lectures about the following definition for acids and bases.

Brut [27]

Answer:

The correct answer is "the Lewis concept of acids and bases".

6 0

3 years ago