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3 years ago

HELP ASAP! GIVING BRAINLIEST!! Why would a pendulum stop swinging? Where did the energy go?

Chemistry

2 answers:

kvasek [131]3 years ago

7 0

Answer:

The pendulum would stop swinging because the kinetic energy would slow down for the friction is causing it to slow. The energy would go into potential energy.

galina1969 [7]3 years ago

7 0

Answer:

friction/heat

Explanation:

the pendulum would eventually stop swinging dude to friction in the air. the friction makes heat even if it is the smallest amount it is still energy. the pendulum would eventually stop due to friction which makes heat

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What device is used to measure atmospheric pressure

yuradex [85]

A Barometer is used to mesure atmosphereic pressure

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3 years ago

Balance Equation<br><br><br> _____N2+_____H2----->_____NH3

Alex Ar [27]

0 N2 + 2 H2 = 2 NH3

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3 years ago

I need to fix the equations

marishachu [46]

Answer:

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Explanation:

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3 years ago

When a 3.25 g sample of solid sodium hydroxide was dissolved in a calorimeter in 100.0 g of water, the temperature rose from 23.

sertanlavr [38]

Answer : The enthalpy change for the solution is 42.8 kJ/mol

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m\times c_2\times \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the water

$c_1$ = specific heat of calorimeter = $15.8J/^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m$ = mass of water = 100.0 g

$\Delta T$ = change in temperature = $T_2-T_1=(32.0-23.9)=8.1^oC$

Now put all the given values in the above formula, we get:

$q=[(15.8J/^oC\times 8.1^oC)+(100.0g\times 4.18J/g^oC\times 8.1^oC)]$

$q=3513.8J=3.5138kJ$ (1 kJ = 1000 J)

Now we have to calculate the enthalpy change for the solution.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 3.5138 kJ

m = mass of NaOH = 3.25 g

Molar mass of NaOH = 40 g/mole

$\text{Moles of }NaOH=\frac{\text{Mass of }NaOH}{\text{Molar mass of }NaOH}=\frac{3.25g}{40g/mole}=0.0812mole$

Now,

$\Delta H=\frac{3.5138kJ}{0.0821mole}=42.8kJ/mol$

Therefore, the enthalpy change for the solution is 42.8 kJ/mol

4 0

3 years ago

Match reagents as starting materials for the synthesis of ethyl 3-phenyl-3-oxopropanate. You can draw out the structures on your

d1i1m1o1n [39]

Explanation:

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8 0

3 years ago