1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeka57 [31]
3 years ago
10

HELP ASAP! GIVING BRAINLIEST!! Why would a pendulum stop swinging? Where did the energy go?

Chemistry
2 answers:
kvasek [131]3 years ago
7 0

Answer:

The pendulum would stop swinging because the kinetic energy would slow down for the friction is causing it to slow. The energy would go into potential energy.

galina1969 [7]3 years ago
7 0

Answer:

friction/heat

Explanation:

the pendulum would eventually stop swinging dude to friction in the air. the friction makes heat even if it is the smallest amount it is still energy. the pendulum would eventually stop due to friction which makes heat

You might be interested in
Are diamonds flammable?
Debora [2.8K]
A match-head is flammable, but you have to get it up to its ignition temperature first.

A diamond is flammable, but its ignition temperature is astronomical and
totally out of sight.
4 0
3 years ago
Read 2 more answers
If a combination reaction takes place between potassium and chlorine what is the product
zepelin [54]
It would be potassium chloride or kcl
4 0
3 years ago
A K+ ion is similar to a Cl– ion in that they both have the same A) nuclear charge B) number of electrons C) atomic number D) nu
pshichka [43]

Answer:

B) number of electrons

Explanation:

The two species:

          K+   and Cl- have the same number of electrons.

A neutral atom of K has 19 electrons

A neutral atom of Cl has 17 electrons

Now,

 To form K+, K will have to lose an electron and then the number of electrons becomes 18

To form Cl-, Cl will have to gain an electrons and then the number of electrons becomes 18

So, therefore, the number of electrons on both species is 18

3 0
2 years ago
The half-life of krypton-91 (91Kr) is 10 s. At time t = 0 a heavy canister contains 7 g of this radioactive gas. (a) Find a func
Vlad1618 [11]

Answer:

misteri Cell ini quest ia half-life of beauty of misteri best, of Cell can't answer =

Explanation:

\sqrt[ \geqslant  { { | \geqslant  | \geqslant  \sqrt[ \gamma \% log_{ \tan( \sqrt[ < \pi \sqrt[ | \geqslant  \sqrt[ <  \leqslant  |x| ]{y} |  \times \frac{?}{?} ]{?} ]{?} ) }(?) ]{?} | | }^{2} }^{?} ]{ \sqrt[ <  \gamma  log_{ \frac{ | \geqslant y \sqrt[ |x \sqrt{ |?| } | ]{?} | }{?} }(?) ]{?} }

5 0
2 years ago
Elements with the same number of shells are called?
ladessa [460]
Element with the same number of shells is element with the same period in periodic table,while element with the same numbers of valence electron is element in the same group .it also have similar chemical properties but different physical properties
4 0
2 years ago
Other questions:
  • In an ionic compound, every ion _____.
    11·2 answers
  • The pH of a solution is 8.83±0.048.83±0.04 . What is the concentration of H+H+ in the solution and its absolute uncertainty?
    6·1 answer
  • H2O is a single atom of water
    14·1 answer
  • How many grams of H2 are needed to react with 47 grams of N2 to produce 200 grams of NH3?
    9·1 answer
  • Rows on the period table are called ______While columns are called_____.
    7·1 answer
  • A home remodeling company charges $10 per square yard for installing new carpets. What is the cost for installing a carpet for a
    9·1 answer
  • .If a 20kg bicycle at the bottom of a hill has speed of 25m/s, how high can the cart go up the hill?
    8·1 answer
  • If two gases, A and B, in separate 1 liter containers exert
    15·1 answer
  • According to Boyle’s law, when the pressure of a gas increases at constant temperature, its volume
    15·1 answer
  • From a cross between a short-haired guinea pig (hh) and a long-haired guinea pig (Hh), what would be the possible phenotypes of
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!