3.16 X 10^-11 M is the [OH-] concentration when H3O+ = 1.40 *10^-4 M.
Explanation:
data given:
H30+= 1.40 X 10^-4 M\
Henderson Hasslebalch equation to calculate pH=
pH = -log10(H30+)
putting the values in the equation:
pH = -log 10(1.40 X 10^-4 M)
pH = 3.85
pH + pOH =14
pOH = 14 - 3.85
pOH = 10.15
The OH- concentration from the pOH by the equation:
pOH = -log10[OH-]
10.5= -log10[OH-]
[OH-] = 10^-10.5
[OH-] = 3.16 X 10^-11 is the concentration of OH ions when hydronium ion concentration is 1.40 *10^-4 M.
They are atoms like hydrogen oxygen or nitrogen
Answer:
It does not contain free mobile ions
Explanation:
Solid sodium chloride does not conduct electricity because it does not contain free mobile ions.
- Although sodium chloride is an ionic compound, in solid state, there is absence of free mobile ions.
- In aqueous solutions or in molten form, ionic compounds can conduct an electric current using free mobile ions as carriers.
- Therefore, they are electrolytes.
In solid state ions are arranged into crystal lattice and will not conduct a current of electricity.