C = 4 mol/l
v = 0.5 l
n(NaCl)=cv
n(NaCl) = 4 mol/l · 0.5 l = 2 mol
2 moles of NaCl must be dissolved
I think it would be C.100.5cm or D.100.5ml hope that helps
False, our tongue and nose work together
Answer:
44
Explanation:
Given that :
Mass of solute = Mass of urea = 16g
Mass of water = 20g
Mass of solution = (mass of solute + mass of solvent) = (mass of urea + mass of water) = (16g + 20g) = 36g
Percentage Mass = (mass of solute / mass of solution) * 100%
Percentage Mass = (16 / 36) * 100%
Percentage Mass = 0.4444444 x 100%
Percentage Mass = 44.44%
Percentage Mass = 44%
Answer:
2.78 moles of water are produced.
Explanation:
Given data:
Number of moles of H₂O produced = ?
Number of moles of oxygen react = 3.25 mol
Solution:
Chemical equation:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
Now we will compare the moles of water with oxygen.
O₂ : H₂O
7 : 6
3.25 : 6/7×3.25 = 2.78 mol
