Th actual yield of the reaction is 24.86 g
We'll begin by calculating the theoretical yield of the reaction.
2Na + Cl₂ → 2NaCl
Molar mass of Na = 23 g/mol
Mass of Na from the balanced equation = 2 × 23 = 46 g
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Mass of NaCl from the balanced = 2 × 58.5 = 117 g
From the balanced equation above,
46 g of Na reacted to produce 117 g of NaCl.
Therefore,
11.5 g of Na will react to produce = (11.5 × 117) / 46 = 29.25 g of NaCl.
Thus, the theoretical yield of NaCl is 29.25 g.
Finally, we shall determine the actual yield of NaCl.
- Theoretical yield = 29.25 g
Actual yield = Percent yield × Theoretical yield
Actual yield = 85% × 29.25
Actual yield = 0.85 × 29.25 g
Actual yield = 24.86 g
Learn more about stoichiometry: brainly.com/question/25899385
The number of moles contained in 39 L of F2 gas at STP is 1.74mol. Details on how to calculate number of moles can be found below.
<h3>How to calculate number of moles?</h3>
The number of moles of a gas at STP can be calculated using the following formula:
PV = nRT
Where;
- P = pressure
- V = volume
- n = number of moles
- R = gas law constant
- T = temperature
At STP, the following applies:
- T = 273K
- P = 1 atm
- R = 0.0821 Latm/molK
1 × 39 = n × 0.0821 × 273
39 = 22.41n
n = 1.74mol
Therefore, the number of moles contained in 39 L of F2 gas at STP is 1.74mol.
Learn more about number of moles at: brainly.com/question/14919968
Answer:
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