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White raven [17]
3 years ago
7

If crystal growth does not start on its own after the solution in the flask returns to room temperature, identify the best ways

to promote this process. Select one or more: Add a bit of solid as a seed crystal. Scratch the bottom of the flask gently with a stirring rod. Place the flask on a hot plate to evaporate some solvent. Add ice cubes to the solution.
Chemistry
1 answer:
deff fn [24]3 years ago
7 0

Answer: The best way to promote the process are:

--> Add a bit of solid as a seed crystal.

--> Scratch the bottom of the flask gently with a stirring rod.

Explanation:

A crystal growth is seen is SUPERSATURATED solutions which contains more solute than it can normally dissolve at that given temperature. It is usually very UNSTABLE and capable of releasing the excess solute if disturbed, either by shaking or seeding with a tiny crystals.

Crystallization can be used for the separation of two salts with different solubilities as well as for purification of a soluble salt that contains insoluble solid impurities. Recrystallization improves the validity of the process. Crystallization can be initiated by:

--> Scratching the bottom of the flask gently with a stirring rod: scratching initiates crystallization by providing energy from the high-frequency vibrations.

--> Adding a bit of solid as a seed crystal: Seed crystals create a nucleation site where crystals can begin growth.

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julsineya [31]

Answer:

The volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml

Explanation:

Here we have the reaction of AgNO₃ and NaCl as follows;

AgNO₃(aq) + NaCl(aq)→ AgCl(s) + NaNO₃(aq)

Therefore, one mole of silver nitrate, AgNO₃, reacts with one mole of sodium chloride, NaCl, to produce one mole of silver choride, AgCl, and one mole of sodium nitrate, NaNO₃,

Therefore, since 5.84 grams of NaCl which is 58.44 g/mol, contains

Number \, of \, moles, n  = \frac{Mass}{Molar \ mass} =  \frac{5.84}{58.44} = 0.09993 \ moles \ of \ NaCl

0.09993 moles of NaCl will react with 0.09993 moles of AgNO₃

Also, as 1.0 M solution of AgNO₃ contains 1 mole per 1 liter or 1000 mL, therefore, the volume of AgNO₃ that will contain 0.09993 moles is given as follows;

0.09993 × 1 Liter/mole= 0.09993 L = 99.93 mL

Therefore, the volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml.

3 0
4 years ago
What volume. In liters, of H2O(g) measured at STP is produced by the combustion of 15.63 g of natural gas (CH4) according to the
fomenos

Answer:

V = 43.95 L

Explanation:

Given data:

Mass of CH₄ decomposed = 15.63 g

Volume of H₂O produced at STP = ?

Solution:

Chemical equation:

CH₄ + 2O₂    →       2H₂O  + CO₂

Number of moles of CH₄:

Number of moles = mass/molar mass

Number of moles = 15.63 g/ 16 g/mol

Number of moles = 0.98 mol

Now we will compare the moles of H₂O with CH₄.

                         CH₄              :              H₂O

                           1                 :                2

                        0.98             :            2×0.98 = 1.96 mol

Volume of hydrogen:

PV = nRT

1 atm × V = 1.96 mol × 0.0821 atm.L/mol.K × 273.15 K

V = 43.95atm.L / 1atm

V = 43.95 L

3 0
3 years ago
1, 2 and 3 ........
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8 0
3 years ago
The reducing agent in the reaction described in Fe + 2HCl → FeCl2 + H2 is A. H2. B. Fe. C. HCl. D. FeCl2.
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The reducing agent is b). Fe
7 0
3 years ago
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Which equation represents a double replacement reaction?
AveGali [126]

Answer:

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General Formulas and Concepts:

<u>Chemistry - Reactions</u>

  • Synthesis Reactions: A + B → AB
  • Decomposition Reactions: AB → A + B
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Explanation:

<u>Step 1: Define</u>

RxN A:   2Na + 2H₂O → 2NaOH + H₂

RxN B:   CaCO₃ → CaO + CO₂

RxN C:   LiOH + HCl → LiCl + H₂O

RxN D:   CH₄ + 2O₂ → CO₂ + 2H₂O

<u>Step 2: Identify</u>

RxN A:   Single Replacement Reaction

RxN B:   Decomposition Reaction

RxN C:   Double Replacement Reaction

RxN D:   Combustion Reaction

7 0
3 years ago
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