Answer:
The cadmium carbonate (CdCO3) will precipitate first.
We need 6.9 *10^-11 M CO3^2- to initiate precipitation.
Explanation:
<u>Step 1:</u> Given data
The solution contains
⇒ 1.12*10^-2 M Fe2+
⇒ 1.45*10^−2 M Cd2+
The Ksp of CdCO3 is 10^-12
The Ksp of FeCO3 is 3.13 * 10^-11
<u>Step 2:</u> Calculate concentration of CO3^2- in FeCO3
FeCO3(s) ⇔ Fe2+ + CO3^2- Ksp = 3.1*10^-11
Ksp = [Fe2+][CO3^2-]
[CO3^2-] = Ksp / [Fe2+]
[CO3^2-] = 3.13*10^-11 / 1.12*10^-2
[CO3^2-] = 2.795 * 10^-9 M
<u>Step 3:</u> Calculate concentration of CO3^2- in CdCO3
CdCO3(s) ⇔Cd^2+ + CO3^2- Ksp = 10^-12
Ksp = [Cd2][CO3^2-]
[CO3^2-] = Ksp /[Cd^2+]
[CO3^2-] = 10^-12 / 1.45x10^-2
[CO3^2-] =6.9 *10^-11 M
The cadmium carbonate (CdCO3) will precipitate first.
We need 6.9 *10^-11 M CO3^2- to initiate precipitation.
Natural formation of lead occurs by radioactive decay of uranium and thorium through radon (222Rn). Four stable isotopes are known, 204Pb, 206Pb, 207Pb and 208Pb, the first three of which are used for estimating the ages of rocks. Lead compounds exist mainly in +2 or +4 oxidation states, the former being more common.
Answer:
6 moles of C atoms, 12 moles of H atoms and 6 moles of O atoms
Explanation:
A chemical formula represents the number of moles of atoms presents in 1 mole of the compound.
For example, for 1 mole:
CₐHₓ, you have a moles of carbon and x moles of hydrogen.
Thus, for the molecule:
C₆H₁₂O₆, you have <em>6 moles of C atoms, 12 moles of H atoms and 6 moles of O atoms</em>
Answer:
An oxidation-reduction (redox) reaction is a type of chemical reaction that involves a transfer of electrons between two species. An oxidation-reduction reaction is any chemical reaction in which the oxidation number of a molecule, atom, or ion changes by gaining or losing an electron.
Explanation:
Answer: OB The candles are able to burn
Explanation: OA The cnadles are thin is a description, OC The candles are 10 cm tall is descriptive , OD The candles are blue is descriptive
