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3 years ago

Is the boron neutral atom or ion?

Chemistry

1 answer:

ira [324]3 years ago

5 0

Answer:

Boron would have a

charge.

Explanation:

Boron has an atomic number of

. For an atom to be an ion, it wants to have full electron shells with the "minimum number" (this is hard to explain). So that means that boron would either want

electrons or

electrons. Of course, it would be easier to have

electrons from

electrons, so there it will lose

electrons, and would have a final charge of

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What is the temperature of 0.500 moles of a gas that is stored in a 2.50 L container under 13.0 atm of pressure?

faust18 [17]

<h2>Answer:</h2>

Moles of a gas = 0.500

Volume = 2.50 L

Pressure = 13. atm

Temperature = ?

Solution:

Formula:

PV = n RT

Putting the values in formula:

T = PV/nR = 13 * 2.5 / 0.5 * 0.082057

= 32.5/0.041 = 792.68 K

T = 792.68 K

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3 years ago

In real-life situations, workers collect water samples in a lake or stream instead of using Samples A and B. For this lab to wor

Aloiza [94]

The given above pretty much states already that with the presence of the calcium carbonate which acts as the buffer will allow the solution to withstand changes in acidity. The greater the amount, the higher chances that it will be able to withstand the said changes. Therefore, if Lake X had greater ppm of CaCO3 then, it will be able to withstand greater amount of acid rain.

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2 years ago

For the following electrochemical reaction: Al3+(aq) + 3e -> Al(s) Eº = -1.66 V E° = 2.87 F2(g) + 2e -> 2F (aq) Calculate

makvit [3.9K]

<u>Answer:</u> The standard electrode potential of the cell is 4.53 V.

<u>Explanation:</u>

We are given:

$E^o_{(F_2/F^-)}=2.87V\\E^o_{(Al^{3+}/Al)}=-1.66V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Aluminium will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=2.87-(-1.66)=4.53V$

Hence, the standard electrode potential of the cell is 4.53 V.

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2 years ago

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Travka [436]

Answer:

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Explanation:

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2 years ago

The pKa of lactic acid is 3.9. A lactate buffer will be useful from pH values ________. The pKa of lactic acid is 3.9. A lactate

Vedmedyk [2.9K]

Answer:

Explanation:

The usefulness of a buffer is its ability to resist changes in pH when small quantities of base or acid are added to it. This ability is the consequence of having both the conjugate base and the weak acid present in solution which will consume the added base or acid.

This capacity is lost if the ratio of the concentration of conjugate base to the concentration of weak acid differ by an order of magnitude. Since buffers having ratios differing by more will have their pH driven by either the weak acid or its conjugate base .

From the Henderson-Hasselbach equation we have that

pH = pKa + log [A⁻]/[HA]

thus

0.1 ≤ [A⁻]/[HA] ≤ 10

Therefore the log of this range is -1 to 1, and the pH will have a useful range of within +/- 1 the pKa of the buffer.

Now we are equipped to answer our question:

pH range = 3.9 +/- 1 = 2.9 through 4.9

7 0

3 years ago