The derivatife is zero, but your differentiating with respect to V so just treat the constants as numbers and differentiate accordingly

d(nRT/(V-nb))dV = -nRT/ (V-nb)^2

and

d (-an^2/V^2) dV = 2an^2/V^3

Hope this helps

6 0

3 years ago

Objects with masses of 255 kg and a 555 kg are separated by 0.390 m.

eimsori [14]

Answer:

(a). The net gravitational force is $4.20\times10^{-6}\ N$

(b). The position is at 0.232 m.

Explanation:

Given that,

Mass of one object M = 255 kg

Mass of another object M'= 555 kg

Separation = 0.390 m

(a). We need to calculate the net gravitational force

Using formula of force

$F_{net}=\dfrac{GM'm}{r^2}-\dfrac{GMm}{r^2}$

$F_{net}=\dfrac{Gm(M'-M)}{r^2}$

Put the value into the formula

$F_{net}=\dfrac{6.67\times10^{-11}\times32.0(555-255)}{(0.390)^2}$

$F_{net}=4.20\times10^{-6}\ N$

The net gravitational force is $4.20\times10^{-6}\ N$

(b). We need to calculate the position

Force from 555 mass = Force from 255 mass

$\dfrac{Gm\times555}{x^2}=\dfrac{Gm\times255}{(0.390-x)^2}$

$555(0.390-x)^2=255x^2$

$300x^2-0.78x+84.4155=0$

$x=0.232\ m$

The position is at 0.232 m.

Hence, (a). The net gravitational force is $4.20\times10^{-6}\ N$

(b). The position is at 0.232 m.

5 0

3 years ago

Read 2 more answers

Which is the most accurate description of potassium (K)?

Svetllana [295]

D. It will tend to lose an electron in a chemical reaction.

6 0

3 years ago

Read 2 more answers

A Scooter has a mass of 250 kg. A constant force is exerted on it for 6.0 s. During the time the force is exerted, the scooter i

fredd [130]

Answer:

917 N

Explanation:

917 N, this is your answer!!

Glad to help.

5 0

3 years ago