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umka2103 [35]
4 years ago
13

One object has a charge of +5.0 · 10-6 c, and a second object has a charge of +2.0 · 10-6

Physics
1 answer:
ruslelena [56]4 years ago
4 0
The electrostatic force between two charged objects is given by
F=k \frac{q_1 q_2}{r^2}
where
k is the Coulomb's constant
q1 is the charge of the first object
q2 is the charge of the second object
r is the separation between the two objects

In our problem:
q_1=+5.0 \cdot 10^{-6} C
q_2 = +2.0 \cdot 10^{-6} C
r=0.5 m
So if we plug these numbers into the equation, we can find the electrostatic force between the two objects:
F=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(5.0 \cdot 10^{-6} C)(2.0 \cdot 10^{-6}C)}{(0.5 m)^2}=0.36 N
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A new ride being built at an amusement park includes a vertical drop of 126.5 metered. Starting from rest, the ride vertically d
Delvig [45]

Answer:

The amount of Potential Energy lost in the form of Thermal Energy is equal to 41.64 MJ.

Explanation:

mass of the cart and passengers = m = 3.5*10⁴ kg

Height = h = 126.5 m

g = 9.8 ms⁻²

v = 10 ms⁻¹

At the top position the Total energy of the ride is in the form of potential energy given as:

P.E = mgh

= 3.5*10⁴*9.8*126.5

= 43389500 J

At the bottom of the drop, all the Potential Energy will be converted into K.E as the ride develops speed given as:

K.E = 0.5*m*v²

= 0.5*3.5 x 10⁴*100

= 1750000 J

The K.E is much less than the P.E energy even though all the P.E of the ride has been converted. The loss of energy is due to the formation of thermal energy which can be calculated as:

Thermal Energy lost = Total energy in the form of P.E(top) - Total energy in the form of K.E(bottom)

= 43389500 -  1750000

= 41639500 J

= 41.64 M J approx             M J = mega joule = 10⁶ J

7 0
3 years ago
The displacement of a moving object in given interval of time is zero . Would the distance travelled by the object also be zero.
kirill [66]





Hi Pupil Here's Your answer ::




➡➡➡➡➡➡➡➡➡➡➡➡➡



No, on a circle in going from one point around circular path the displacement is zero but the distance covered is equal to the circumference of the circle.

i.e.


2\pi r


⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅




Hope this helps . . . . . . .

3 0
3 years ago
Which of the following lies in the ecliptic plane?
babymother [125]
<h2>Answer: Earth's orbital path around the Sun</h2><h2></h2>

The <u>Ecliptic</u> refers to the orbit of the Earth around the Sun. Therefore, <u>for an observer on Earth it will be the apparent path of the Sun in the sky during the year, with respect to the "immobile background" of the other stars.</u>

<u />

It should be noted that the ecliptic plane (which is the same orbital plane of the Earth in its translation movement) is tilted with respect to the equator of the planet about 23\° approximately. This is due to the inclination of the Earth's axis.

Hence, the correct option is Earth's orbital path around the Sun.

7 0
4 years ago
Two extremely large nonconducting horizontal sheets each carry uniform charge density on the surfaces facing each other. The upp
sashaice [31]

This problem refers to a parallel plate capacitor. There is an electric field between the two plates. The working equation to be used is the Gauss’s Law which is

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The answer is -2.52 μC/m2.

8 0
3 years ago
___________________ and ___________________________ are two main types of waves.
iris [78.8K]

Answer:

its A

Explanation:

6 0
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