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rewona [7]
3 years ago
5

Two extremely large nonconducting horizontal sheets each carry uniform charge density on the surfaces facing each other. The upp

er sheet carries +5.00 µC/m2. The electric field midway between the sheets is 4.25 × 105 N/C pointing downward. What is the surface charge density on the lower sheet? (ε0 = 8.85 × 10-12 C2/N · m2)
Physics
1 answer:
sashaice [31]3 years ago
8 0

This problem refers to a parallel plate capacitor. There is an electric field between the two plates. The working equation to be used is the Gauss’s Law which is

Electric field = Surface charge density / ε0

The answer is -2.52 μC/m2.

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Answer: final Displacement = 0 km, total distance covered =7 km

Explanation:

Given the following :

From home to library = 1.3 km East

Library to music store = 0.68km East

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Displacement is the net change in distance traveled.

Eastward distance :

To = (1.3 + 0.68)km = 1.98km East

Fro = (0.68 + 1.3)km = 1.98 km East

Δ distance = (1.98 - 1.98) = 0

Northward direction:

To = (1.1 + 0.42)km = 1.52km north

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Δ distance = (1.98 - 1.98) = 0

Hence final Displacement = 0

Total distance covered = 2 × (1.3 + 0.68 + 1.1 + 0.42) = 2 × 3.5

= 7km

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