Answer:
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.
So for the book.

What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)
This is 1 subtracted by the pvalue of Z when X = 20.2. So



has a pvalue of 0.8980
1 - 0.8980 = 0.1020
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Answer:
b
Step-by-step explanation:
53/100 ÷ 5 can be reduced down to
7
-----
20
Good Luck! :)
Answer:
Step-by-step explanation:
(-3x + 2)(45x + 21) + (-4x + 25) = 50
-135x^2 - 63x + 90x + 42 - 4x + 25 = 50
-135x^2 + 23x + 67 = 50
-135x^2 + 23x + 67 - 50 = 0
-135x^2 + 23x + 17 = 0
quadratic formula : x = (-b ± √b^2 - 4ac)/2a
a = -135, b = 23, c = 17
x = -23 ± √23^2 - 4(-135)(17) / (2(-135)
x = (-23 ±√9709 )/ -270
x = 23/270 ± 1 / 270√9709/270
x = 0.4501 or x = - 0.2798 <=== these answers are rounded
Answer:
b
Step-by-step explanation: