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3 years ago

A scientific idea becomes valid when it is

Physics

1 answer:

SIZIF [17.4K]3 years ago

7 0

Answer:

are adopted when they usefully describe the world. evidence

Explanation:

A scientific idea is validated when it is published in the peer-reviewed literature in the field, has stood up to further tests, and has been positively cited.

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A car is traveling to the right with a speed of 29m/s when the rider slams on the accelerator to pass another car. The car pas

adoni [48]

Answer:

Acceleration of the car is $1.43\ m/s^2$ .

Explanation:

It is given that,

Initial speed of the car, u = 29 m/s

Finally it reaches a speed of, v = 34 m/s

Distance, d = 110 m

We need to find the acceleration of the car as it speed up. It can be calculated using third law of motion as :

$v^2-u^2=2ad$

$a=\dfrac{v^2-u^2}{2d}$

$a=\dfrac{(34)^2-(29)^2}{2\times 110}$

$a=1.43\ m/s^2$

So, the acceleration of the car as it speeds up is $1.43\ m/s^2$ . Hence, this is the required solution.

6 0

3 years ago

In this unit, the amount of solute is measured in?

Hoochie [10]

Try liters if you haven’t done it yet. I’m so sorry if i’m incorrect.

5 0

2 years ago

Read 2 more answers

A 10.0 L tank contains 0.329 kg of helium at 28.0 ∘C. The molar mass of helium is 4.00 g/mol . Part A How many moles of helium a

nadya68 [22]

Answer:

82.25 moles of He

Explanation:

From the question given above, the following data were obtained:

Volume (V) = 10 L

Mass of He = 0.329 Kg

Temperature (T) = 28.0 °C

Molar mass of He = 4 g/mol

Mole of He =?

Next, we shall convert 0.329 Kg of He to g. This can be obtained as follow:

1 Kg = 1000 g

Therefore,

0.329 Kg = 0.329 Kg × 1000 g / 1 Kg

0.329 Kg = 329 g

Thus, 0.329 Kg is equivalent to 329 g.

Finally, we shall determine the number of mole of He in the tank. This can be obtained as illustrated below:

Mass of He = 329 g

Molar mass of He = 4 g/mol

Mole of He =?

Mole = mass / molar mass

Mole of He = 329 / 4

Mole of He = 82.25 moles

Therefore, there are 82.25 moles of He in the tank.

8 0

2 years ago

The core of a certain reflected reactor consist of a cylinder 10 ft high 10 ft in diameter The measured maximum-to-average flux

Westkost [7]

Answer:

The maximum power density in the reactor is 37.562 KW/L.

Explanation:

Given that,

Height = 10 ft = 3.048 m

Diameter = 10 ft = 3.048 m

Flux = 1.5

Power = 835 MW

We need to calculate the volume of cylinder

Using formula of volume

$V =\pi r^2 h$

Put the value into the formula

$V=\pi\times(1.524)^2\times 3.048$

$V= 22.23\m^3$

$V = 22.23\times10^{3}\ Liter$

We need to calculate the maximum power density in the reactor

Using formula of power density

$P=\dfrac{E}{V}$

Where, P = power density

E = energy

V = volume

Put the value into the formula

$P=\dfrac{835\times10^{6}}{22.23\times10^{3}}$

$P=37561.85 = 37.562\times KW/L$

Hence, The maximum power density in the reactor is 37.562 KW/L.

6 0

3 years ago

In order to be accepted, a scientific theory must be

bija089 [108]

Answer:

The answer is the 1st one

6 0

2 years ago