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ycow [4]
1 year ago
12

A brick sliding across a smooth floor has a coefficient of static friction of s=0.23 and a coefficient of kinetic friction of k=

0.15. If the brick has a mass of 0.85 kg, how much friction will the brick experience as it slides?
Physics
2 answers:
Marianna [84]1 year ago
5 0

Answer:

1.25 N

Explanation:

It will experience friction from the kinetic friction component because it is moving ...there will be no component of static friction.

Ff = F n x  k

   =   (.85)(9.81)  x (.15) = 1.25 N

pantera1 [17]1 year ago
4 0

Answer:

0.029325

Explanation:

0.23x0.15=0.0345

0.0345x0.85=0.029325

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3 years ago
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What is the change in internal energy if 60 J of heat is released from a system and 30 J of work is done on the system? Use U =
k0ka [10]

The change in internal energy of the system is +30 J

Explanation:

We can solve this problem by using the first law of thermodynamics, which states that the change in internal energy of a system is given by the equation:

\Delta U = Q -W

where

\Delta U is the change in internal energy

Q is the heat absorbed by the system (positive if it is absorbed, negative if it is released)

W is the work done by the system (positive if it is done by the system, negative if it is done by the surroundings on the system)

Therefore, in this problem, we have

Q=-60 J (heat released by the system)

W=-30 J (work done on the system)

Therefore, the change in internal energy is

\Delta U = -60 - (-30) = +30 J

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8 0
3 years ago
For safety reasons, a worker’s eye travel time in a certain operation must be separated from the manual elements that follow. Th
iogann1982 [59]

Answer:

The answer is 12.67 TMU

Explanation:

Recall that,

worker’s eyes travel  distance must be = 20 in.

The perpendicular distance from her eyes to the line of travel is =24 in

What is the MTM-1 normal time in TMUs that should be allowed for the eye travel element = ?

Now,

We solve for the given problem.

Eye travel is = 15.2 * T/D

=15.2 * 20 in/24 in

so,

= 12.67 TMU

Therefore, the MTM -1 of normal time that should be allowed for the eye  travel element is = 12.67 TMU

7 0
3 years ago
a tire with inner volume of 0.0250m^3 is filled with air at a gauge pressure of 36.0 psi. If the tire valve is opened to the atm
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Answer: Escaped volume = 0.0612m^3

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P1 = initial pressure in the tire = 36.0psi + 14.696psi = 50.696psi (guage + atmospheric pressure)

P2 = atmospheric pressure= 14.696psi

V1 = volume of tire =0.025m^3

V2 = escaped volume + V1 ( since air still remain in the tire)

V2 = P1V1/P2

V2 = 50.696×0.025/14.696

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2 years ago
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Answer:

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