The given expression is:
![\sqrt[5]{64 x^{7} w^{5} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B64%20x%5E%7B7%7D%20%20w%5E%7B5%7D%20%7D%20)
The expression can be simplified as follows:
![\sqrt[5]{64 x^{7} w^{5} } \\ \\ = \sqrt[5]{(2)^{6} x^{7} w^{5} } \\ \\ = \sqrt[5]{(2)^{5}*2* x^{5}* x^{2} * w^{5} } \\ \\ = \sqrt[5]{ (2^{5} x^{5} w^{5} )*2 x^{2} } \\ \\ = \sqrt[5]{(2xw)^{5}*2 x^{2} } \\ \\ =2xw* \sqrt[5]{2x^{2} } ](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B64%20x%5E%7B7%7D%20w%5E%7B5%7D%20%7D%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%282%29%5E%7B6%7D%20%20x%5E%7B7%7D%20%20w%5E%7B5%7D%20%7D%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%282%29%5E%7B5%7D%2A2%2A%20x%5E%7B5%7D%2A%20x%5E%7B2%7D%20%2A%20w%5E%7B5%7D%20%20%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%20%282%5E%7B5%7D%20%20x%5E%7B5%7D%20%20w%5E%7B5%7D%20%29%2A2%20x%5E%7B2%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%282xw%29%5E%7B5%7D%2A2%20x%5E%7B2%7D%20%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D2xw%2A%20%5Csqrt%5B5%5D%7B2x%5E%7B2%7D%20%7D%20%0A%20)
The expression can be simplified as follows:
A trash can in the shape of a cylinder has a radius of 26 cm and a height of 39 cm. Which of the following is closest to the vol
1 answer:
Answer:
The volume of cylindrical trash is 82,782.96 cm³ .
Step-by-step explanation:
Given as :
The shape of the trash is cylinder
The radius of cylinder = r = 26 cm
The height of cylinder = h = 39 cm
Let The volume of cylindrical trash = v cm³
<u>Now, According to question</u>
volume =
where = 3.14
So, v = 3.14 × r² × h
Or, v = 3.14 × (26)² × (39)
Or, v = 3.14 × 26,364
∴ v = 82,782.96 cm³
So, volume of cylindrical trash = v = 82,782.96 cm³
Hence, The volume of cylindrical trash is 82,782.96 cm³ . Answer
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