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Scrat [10]
3 years ago
13

On a boat, a cabin's window is in the shape of an isosceles trapezoid, as shown below. What is the area of the window?

Mathematics
1 answer:
Luba_88 [7]3 years ago
7 0

Answer:

The area of the window will be equal to 195 sq. inches.

Step-by-step explanation:

On a boat, a cabin's window is in the shape of an isosceles trapezoid.

The longer side parallel side is at the bottom.

The top side of the trapezoid is 10 inches and the height is 15 inches and the base of the triangle formed from the height on the right is labeled 3 inches.

So, the bottom parallel side has length of (10 + 3 + 3) = 16 inches.

Therefore, the area of the window will be equal to \frac{1}{2}(10 + 16)15 = 195 sq. inches. (Answer)

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Answer:

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Step-by-step explanation:

6 0
3 years ago
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2 In eIn2x - In eIn 10x = In 30<br>x=30<br>x=75<br>x= 150<br>x=300​
Alex_Xolod [135]

The value of x = 75 ⇒ 2nd answer

Step-by-step explanation:

Let us revise some rules of logarithmic function

  • ln(a) - ln(b)=ln(\frac{a}{b})
  • e^{ln(a)}=a
  • ln(a)^{n}=nln(a) vice-versa nln(a)=ln(a)^{n}
  • If ㏑(a) = ㏑(b), then a = b

∵ 2ln(e^{ln(2x)})-ln(e^{ln(10x)})=ln(30)

- Use the 2nd rule to simplify it

∵ e^{ln(2x)}=2x

∵ e^{ln(10x)}=10x

∴ 2㏑(2x) - ㏑(10x) = ㏑(30)

- Use the 3rd rule in the 1st term

∵ 2㏑(2x) = ㏑(2x)² = ㏑(4x²)

∴ ㏑(4x²) - ㏑(10x) = ㏑(30)

- Use the 1st rule with the left hand side

∵ ln(4x^{2})-ln(10x)=ln(\frac{4x^{2}}{10x})

∴ ln(\frac{4x^{2}}{10x})=ln(30)

∵ \frac{4x^{2}}{10x}=\frac{2x}{5}=\frac{2}{5}x

∴ ln(\frac{2}{5}x)=ln(30)

- Use the 4th rule

∴ \frac{2}{5} x = 30

- Multiply both sides by 5

∴ 2 x = 150

- Divide both sides by 2

∴ x = 75

The value of x = 75

Learn more:

You can learn more about logarithmic functions in brainly.com/question/11921476

#LearnwithBrainly

8 0
3 years ago
What is the length of line segment PQ? If you can please explain, thanks.
nydimaria [60]

Given:

Tangent segment MN = 6

External segment NQ = 4

Secant segment NP =x + 4

To find:

The length of line segment PQ.

Solution:

Property of tangent and secant segment:

If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.

\Rightarrow NQ\times NP = MN^2

\Rightarrow 4\times (x+4) = 6^2

\Rightarrow 4x+16 = 36

Subtract 16 from both sides.

\Rightarrow 4x+16-16 = 36-16

\Rightarrow 4x =20

Divide by 4 on both sides.

$\Rightarrow\frac{4x}{4}=\frac{20}{4}

\Rightarrow x = 5

The length of line segment PQ is 5 units.

5 0
4 years ago
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An observer is standing in a lighthouse 96 feet above the level of the water. The angle of depression of a buoy is 22. What is t
lorasvet [3.4K]
Tan(theta)=opp/adj
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4 0
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Without solving, NO SOLUTION describes which equation?
CaHeK987 [17]

Answer:

The equation 'y = y + 1' represents NO SOLUTION.

Hence, option 'C' is true.

Step-by-step explanation:

a)

6a = 9a

subtract 9a from both sides

6a - 9a = 9a - 9a

-3a = 0

divide both sides by -3

-3a / -3 = 0/-3

Simplify

a = 0

b)

5x = 28

divide both sides by 5

5x/5 = 28/5

x = 28/5

c)

y = y + 1

subtract y from both sides

y - y = y+1-y

0 = 1

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NO SOLUTION!

d)

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y + 5 - 5 = 12 - 5

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Conclusion:

Therefore, the equation 'y = y + 1' represents NO SOLUTION.

Hence, option 'C' is true.

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