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Lina20 [59]
3 years ago
9

What determines the electrical resistance of a conductor?​

Physics
1 answer:
Vesna [10]3 years ago
8 0

Answer:

because

Explanation:

The resistance of a conductor is directly proportional to its length L as R.Thus doubling its resistance while halving its length would halve its resistance .The resistivity of a particular material is measured in units of Ohm-Metres which is also affected by temperature.

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A physicist drives through a stop light. When he is pulled over, he tells the police officer that the Doppler shift made the red
Orlov [11]

The physicist traveling, according to his own testimony at -6.6 × 10⁷ m/s.

<h3>How fast was the physicist traveling, according to his own testimony?</h3>

Using the formula for doppler shift for light,

λ' = λ√[(1 + v/c)/(1 - v/c)] where

  • λ = wavelength of source,
  • λ' = wavelength of observer,
  • v = speed of source and
  • c = speed of light

Given that the driver is moving away from the stop light, we take the driver as the source. Since, the Doppler shift made the red light of wavelength 650nm appear green to him, with a wavelength of 520nm. we have

  • λ' = wavelength of source = 650 nm,
  • λ' = wavelength of observer = 520 nm

So, substituting the values of the variables into the equation, we have

λ' = λ√[(1 + v/c)/(1 - v/c)]

520 nm = 650 nm√[(1 + v/c)/(1 - v/c)]

520/650 = √[(1 + v/c)/(1 - v/c)]

0.8 = √[(1 + v/c)/(1 - v/c)]

Squaring both sides, we have

0.8² = (1 + v/c)/(1 - v/c)

0.64 = (1 + v/c)/(1 - v/c)

0.64(1 - v/c) = (1 + v/c)

0.64 - 0.64v/c = 1 + v/c

0.64 - 1 = v/c + 0.64v/c

-0.36 = 1.64v/c

-0.2195 = v/c

v = -0.22c

v = -0.22 × 3 × 10⁸ m/s

v = -0.66 × 10⁸ m/s

v = -6.6 × 10⁷ m/s

So, the physicist traveling, according to his own testimony at -6.6 × 10⁷ m/s.

Learn more about doppler shift for light here:

brainly.com/question/28499579

#SPJ1

5 0
2 years ago
What scenario involves kinetic Energy transform into potential energy
Vinil7 [7]
The object which is projected upwards. The kinetic energy imparted as its launch is converted into potential energy as an object Rises until, at the peak of its motion, all the kinetic energy has been converted to additional potential energy
4 0
4 years ago
Friction can be reduced by using ___________.
allsm [11]

Answer:

Make the surfaces little more smoother. ...

Lubrication is another way to make a surface smoother. ...

Make the object more streamlined. ...

Reduce the Normal force acting between the surfaces in contact. ...

Reduce the contact between the surfaces, so that less number of bonds will be formed.

6 0
3 years ago
Read 2 more answers
What is the gravitational force that two objects would feel if they are 3.5 meters apart? Object 1 has a mass of 10x10^5 kg and
polet [3.4K]

Answer:

1.63 N

Explanation:

F = GMm/r^2

  = (6.67x10^-11)(10x10^5)(3x10^5) / 3.5^2

  = 1.63 N  ( 3 sig. fig.)

6 0
3 years ago
A 3.91 kg cart is moving at 5.7 m/s when it collides with a 4 kg cart which was at rest. They collide and stick together.
Nesterboy [21]

Answer:

<em>The velocity after the collision is 2.82 m/s</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is  

P=mv.  

If we have a system of two bodies, then the total momentum is the sum of the individual momentums:

P=m_1v_1+m_2v_2

If a collision occurs and the velocities change to v', the final momentum is:

P'=m_1v'_1+m_2v'_2

Since the total momentum is conserved, then:

P = P'

Or, equivalently:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

If both masses stick together after the collision at a common speed v', then:

m_1v_1+m_2v_2=(m_1+m_2)v'

The common velocity after this situation is:

\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}

There is an m1=3.91 kg car moving at v1=5.7 m/s that collides with an m2=4 kg cart that was at rest v2=0.

After the collision, both cars stick together. Let's compute the common speed after that:

\displaystyle v'=\frac{3.91*5.7+4*0}{3.91+4}

\displaystyle v'=\frac{22.287}{7.91}

\boxed{v' = 2.82\ m/s}

The velocity after the collision is 2.82 m/s

6 0
3 years ago
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