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denis23 [38]
3 years ago
13

A 8.5 kg brick is dropped onto a 6.5 kg toy truck, which is moving across a level floor at 0.50 m/s. With what velocity do the t

ruck and brick continue to move, after the brick has landed on the truck?
Physics
1 answer:
Kipish [7]3 years ago
3 0

Answer:0.2167 m/s

Explanation:

Given

mass of brick M=8.5 kg

mass of toy truck m=6.5 kg

the velocity of truck u=0.5 m/s

Suppose v is the velocity after brick is landed on the truck

There is no external force acting so momentum is conserved

mu=(M+m)v

v=\dfrac{6.5}{15}\times 0.5\\v=0.2167\ m/s

You might be interested in
Newton first law of motion ?​
maw [93]

Answer:

The law of inertia

Explanation:

A body at rest will remain at rest, and a body in motion will remain in motion unless it is acted upon by an external force

8 0
3 years ago
Read 2 more answers
The mass of the Sun is 1. 99 × 1030 kg. Jupiter is 7. 79 × 108 km away from the Sun and has a mass of 1. 90 × 1027 kg. The gravi
german

The gravitational force is s type of force that has the ability to attract any two objects having mass. The gravitational force will be 4.16\times10^{23}.

<h3>What is the gravitational force?</h3>

The gravitational force is s type of force that has the ability to attract any two objects with mass. Gravitational force tries to pull two masses towards each other.

                      F= G\frac{m_1m_2}{r^{2} }

Given,

mass of the sun (m_1)= 1.99\times10^{23} kg

mass of Jupiter(m_2)= 7.79\times10^{8} kg

distance between the sun and Jupiter (r)= 1.90\times10^{27} m

F= G\frac{m_1m_2}{r^{2} }\\\\\\F=4.16\times10^{23}\times\frac{1.99\times10^{23}\times7.79\times10^{8}}{({1.90\times10^{27})^2} }

F= 4.16\times(10)^{23}   Newton

Hence the gravitational force between the sun and Jupiter will be 4.16\times10^{23}

To learn more about  gravitational force refer to the link:

brainly.com/question/24783651

4 0
2 years ago
water in a cup and a kettle can have the same temperature even though the quantities are different . give reasons​
jekas [21]

Answer:

The reason is because both are exposed to a virtually infinite heat sink, due to the virtually infinite mass  and of the surrounding environment, compared to the sizes of either the cup or the kettle such that the equilibrium temperature, T_{(equilibrium)} reached is the same for both the cup and the kettle as given by the relation;

\infty M_{(environ)} \times  c_{(environ)} \times (T_2 - T_1) = m_{1} \times  c_{(water)} \times (T_3 - T_2) + m_{2} \times  c_{(water)} \times (T_4 - T_2)

Due to the large heat sink, T₂ - T₁ ≈ 0 such that the temperature of the kettle and that of the cup will both cool to the temperature of the environment

Explanation:

4 0
3 years ago
The kitchen in your house measures 10 ft by 10 ft. You need to have 50 footcandles of illumination in the room. How many 60 watt
tekilochka [14]

Answer:

<u>6 bulbs</u> are needed to illuminate the room.

Explanation:

Given:

Measurement of kitchen (A) = 10 ft by 10 ft = 100 sq. ft

Number of footcandles (n) = 50

Lumens emitted by 1 bulb = 834

Number of bulbs (N) = ?

We are also given,

1 foot candle = 1 lumen/sq. ft

So, 50 foot candles = 50 lumens/sq. ft

Now, for an area of 1 sq. ft 50 lumens are emitted.

So, for an area of 100 sq. ft, lumens emitted = 50 × 100 = 5000 lumens

Now, one bulb emits = 834 lumes

Therefore, number of bulbs required for emitting 5000 lumens is given as:

N=\frac{Number\ of\ lumens}{Number\ of\ lumens\ by\ 1\ bulb}\\\\N=\frac{5000}{834}=5.995\approx6

So, 6 bulbs are needed to illuminate the room.

7 0
3 years ago
A 0.4000 kg sample of methanol at 16.0ºC is mixed with 0.4000 kg of water at 85.0ºC. Assuming no heat loss to the surroundings,
AVprozaik [17]

Answer:

T_finalmix = 59.5 [°C].

Explanation:

In order to solve this problem, a thermal balance must be performed, where the heat is transferred from water to methanol, at the end the temperature of the water and methanol must be equal once the thermal balance is achieved.

Q_{water}=Q_{methanol}

where:

Q_{water}=m_{water}*Cp_{water}*(T_{waterinitial}-T_{final})

mwater = mass of the water = 0.4 [kg]

Cp_water = specific heat of the water = 4180 [J/kg*°C]

T_waterinitial = initial temperature of the water = 85 [°C]

T_finalmix = final temperature of the mix [°C]

Q_{methanol}=m_{methanol}*Cp_{methanol}*(T_{final}-T_{initialmethanol})

Now replacing:

0.4*4180*(85-T_{final})=0.4*2450*(T_{final}-16)\\142120-1672*T_{final}=980*T_{final}-15680\\157800=2652*T_{final}\\T_{final}=59.5[C]

4 0
3 years ago
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