Ask question

Ask question

All categories

2 years ago

13

A 8.5 kg brick is dropped onto a 6.5 kg toy truck, which is moving across a level floor at 0.50 m/s. With what velocity do the t

ruck and brick continue to move, after the brick has landed on the truck?

1 answer:

Kipish [7]2 years ago

3 0

Answer:0.2167 m/s

Explanation:

Given

mass of brick M=8.5 kg

mass of toy truck m=6.5 kg

the velocity of truck u=0.5 m/s

Suppose v is the velocity after brick is landed on the truck

There is no external force acting so momentum is conserved

mu=(M+m)v

$v=\dfrac{6.5}{15}\times 0.5\\v=0.2167\ m/s$

You might be interested in

A hot metal bolt of mass 0.06 kg and specific heat capacity 899 J/kg°C is dropped into a calorimeter containing 0.16 kg water at

skad [1K]

Answer:

Explanation:

Given

mass of hot metal $m_1=0.06\ kg$

specific heat $c=889\ J/kg-^{\circ}C$

mass of water $m_2=0.16\ kg$

Temperature pf water $T_2=20^{\circ}C$

Final Temperature $T=25^{\circ}C$

let $T_1$ be the temperature of hot metal ball

Heat lost by heat metal bolt is gained by water in calorimeter

Heat lost by hot metal bolt $Q_1=m\times c\times \Delta T$

$Q_1=0.06\times 889\times (T-25)$

Heat gained by water $Q_2=m_2\times c_w\times \Delta T$

$Q_2=0.16\times 4184\times (25-20)$

$Q_1=Q_2$

$0.06\times 889\times (T-25)=0.16\times 4184\times (25-20)$

$T_1=25+62.75$

$T_1=87.75^{\circ}C$

7 0

2 years ago

The net external force on the propeller of a 3.8 kg model airplane is 8.2 N forward.

monitta

Answer:

<h3>The answer is 2.16 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

f is the force

m is the mass

From the question we have

$a = \frac{8.2}{3.8} \\ = 2.157894736...$

We have the final answer as

<h3>2.16 m/s²</h3>

Hope this helps you

8 0

3 years ago

A thin cylindrical shell is released from rest and rolls without slipping down an inclined ramp that makes an angle of 30° with

NNADVOKAT [17]

Answer: 1.59 sec

Explanation:

The kinetic energy contained in the rotation of the cylinder is 1/2 m v^2

The kinetic energy of translation is also 1/2 m v^2

so the total energy is m v^2

The force applied is mg sin (theta)

= m x 9.8 x 1/2

= 4.9 m

Now equate

F x d = m v^2

4.9 m x 3.1 = m v^2

v^2 = 4.9 x 3.1

v = sqrt(4.9 x 3.1) = 3.9 m/s

Acceleration.

V^2 = 2 a s

4.9 x 3.1 = 2 x a x 3.1

4.9 = 2 a

a = 2.45 m/s^2

Time

T = v/a

= 3.9/2.45

= 1.59 sec

6 0

3 years ago

Carbon show some unique property name them name them

swat32

Answer:

Physical Properties of Carbon:

Carbon is a unique element. It occurs in many forms. Some examples of the pure form of carbon are coal and soot.

It is soft and dull grey or black in colour.

One of the most important compounds of carbon is the charcoal, which is formed when carbon is heated in the absence in of air.

It occurs in a number of allotropic forms. Allotropes are nothing but forms of an element with varying physical as well as chemical properties.

The density of the different forms of carbon depends upon the origin of these elements. You will find some forms of carbon which are pure and some forms which are not pure like coal which is the mixture of both carbon and hydrogen.

Chemical Properties of Carbon

Carbon compounds generally show 4 reactions, they are

Combustion reaction

Oxidation reaction,

Addition reactions

Substitution reaction.

As we all know that carbon in all forms needs oxygen, heat, and light and forms carbon dioxide. When it is burned in air to give carbon dioxide, it is called as combustion.

Let us get the concept of this using some examples when it is burnt in the air: When methane CH4 is burnt in the presence of oxygen it gives us carbon dioxide, heat, and light.

Explanation:

6 0

3 years ago

A uniform meter stick (with a length of 1.00 meter) has a mass of 108 g. It is supported at its midpoint by a vertical rigid blu

alexandr1967 [171]

Answer:4

Explanation:

Given

$m_1=21\ gm$

$m_2=27\ gm$

Mass of stick is $m=108\ gm$

Let T be the tension in the red string

Now if the red string is cut , suppose T is the tension in the blue rod immediately after cut

Therefore

$T=m_1g+m_2g$

$T=(0.021+0.027)\times 10$

$T=0.48\ N$

4 0

3 years ago