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denis23 [38]
3 years ago
13

A 8.5 kg brick is dropped onto a 6.5 kg toy truck, which is moving across a level floor at 0.50 m/s. With what velocity do the t

ruck and brick continue to move, after the brick has landed on the truck?
Physics
1 answer:
Kipish [7]3 years ago
3 0

Answer:0.2167 m/s

Explanation:

Given

mass of brick M=8.5 kg

mass of toy truck m=6.5 kg

the velocity of truck u=0.5 m/s

Suppose v is the velocity after brick is landed on the truck

There is no external force acting so momentum is conserved

mu=(M+m)v

v=\dfrac{6.5}{15}\times 0.5\\v=0.2167\ m/s

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Three forces with magnitudes of 95 pounds, 75 pounds, and 146 pounds act on an object at angles 100°, 200°, and 300°, respective
VladimirAG [237]

Answer:

Explanation:

We shall represent all the forces in vector form .

Force of 95 pounds

F₁ = 95cos100 i + 95sin100j

= -16.5 i +93.55 j

force of 75 pounds

F₂ = 75cos200 + 75sin200j

= -70.47 i - 25.65 j

force of 146 pounds

F₃ = 146cos300 i + 146sin300j

= 73i -126.44 j

Resultant force

R = F₁+ F₂ + F₃

=  -16.5 i +93.55 j  -70.47 i - 25.65 j +73i -126.44 j

= -13.97 i - 58.54 j

Magnitude of R = √ ( 13.97² + 58.54² )

= 60.18

If Ф be angle of resultant with  axis

tanФ = - 58.54 / -13.97

Ф = 76.57 + 180 = 256.57 , because both  x and y components are negative. So the resultant will be in third quadrant.

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3 years ago
What is the scientific notation
svet-max [94.6K]
Its like a shoter way or writing "to the power" I think.
8 0
3 years ago
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Suppose that the strings on a violin are stretched with the same tension and each has the same length between its two fixed ends
lesya692 [45]

Answer:

0.00384 kg/m

Explanation:

The fundamental frequency of string waves is given by

f=\frac{1}{2L}\sqrt{\frac{F}{\mu}}

For some tension (F) and length (L)

f\propto\frac{1}{\mu}

Fundamental frequency of G string

f_G=196\ Hz

Fundamental frequency of E string

f_E=659.3\ Hz

Linear mass density of E string is

\mu_E=3.4\times 10^{-4}\ kg/m

So,

\frac{F_G}{F_E}=\sqrt{\frac{\mu_E}{\mu_G}}\\\Rightarrow \frac{F_G^2}{F_E^2}=\frac{\mu_E}{\mu_G}\\\Rightarrow \mu_G=3.4\times 10^{-4}\times \frac{659.3^2}{196^2}\\\Rightarrow \mu_G=0.00384\ kg/m

The linear density of the G string is 0.00384 kg/m

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3 years ago
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Explanation:

The <em>electromagnetic spectrum</em> is the name given to the full range of frequencies and/or wavelengths that electromagnetic phenomena may have.

Human eyes respond to a small range of wavelengths in that spectrum. That response is called <em>sight</em>. Because humans can see that electromagnetic energy, it is called <em>visible light</em>.

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I think it's force

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