Question 15
1 answer:
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The time taken for him to move the bin 6.5 m is 2.30 s.
The given parameters;
- <em>weight of the load, w = 557 N</em>
- <em>force applied , F = 410 N</em>
- <em>angle of force, = 15°</em>
- <em>coefficient of kinetic friction = 0.46</em>
- <em>distance moved, d = 6.5 m</em>
The net horizontal force on the recycling bin is calculated as follows;
where;
- <em>m is the mass of the recycling bin</em>
- <em />
<em> is the frictional force </em>
W = mg
The net horizontal force on the recycling bin is calculated as;
The time taken for him to move the bin 6.5 m is calculated as follows;
Thus, the time taken for him to move the bin 6.5 m is 2.30 s.
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Answer:
The value is
Explanation:
From the we are told that
The initial speed of the object is
The greatest height it reached is
Generally from kinematic equation we have that
At maximum height v = 0 m/s
So
=>
Here H is the height from the initial height to the maximum height
So the initial height is mathematically represented as
=>
=>
Generally the time taken for the object to reach maximum height is mathematically evaluated using kinematic equation as follows
At maximum height v = 0 m/s
=>
Generally the time taken for the object to move from the maximum height to the ground is mathematically using kinematic equation as follows
Here the initial velocity is 0 m/s given that its the velocity at maximum height
Also g is positive because we are moving in the direction of gravity
So
=>
Generally the total time taken is mathematically represented as
=>
=>
Answer:
Voltage across the capacitor is 30 V and rate of energy across the capacitor is 0.06 W
Explanation:
As we know that the current in the circuit at given instant of time is
i = 2.0 mA
R = 10 k ohm
now we know by ohm's law
so voltage across the capacitor + voltage across resistor = V
Now we know that
here rate of change in energy of the capacitor is given as