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3 years ago

Question 15

Physics

1 answer:

dezoksy [38]3 years ago

4 0

Answer:

Both particle and wave properties

Explanation:

Light is defined as a particle and a wave, and even as a combination of a particle and a wave. A unit of light is the photon. Higher energy photons behave like particles and low energy photons behave like waves.

Experiments performed with light indicate that light exhibits both particle and wave properties.

You might be interested in

Why doesn’t a machine that increases force break the law of conservation of energy?

USPshnik [31]

Answer:

A machine in which work input equals work output. energy can be used to do work, work can be used to transfer energy. The change in the kinetic energy of an object is equal to the net work done on the object.

hope this helps

8 0

3 years ago

What is the kinetic energy in Joules of a 1,500kg car traveling at 75mph?What is the kinetic energy in Joules of a 1,500kg car t

Sergio039 [100]

Answer: 2812500 joules

Explanation:

Mass of car = 1500kg

Velocity of car = 75mph

Kinetic energy = ?

Recall that kinetic energy is the energy possessed by a moving object, and it depends on its mass M and velocity, V

Thus, Kinetic energy = 1/2 x mv^2

= 1/2 x 1000kg x (75mph)^2

= 0.5 x 1000kg x (75mph)^2

= 500 x 5625

= 2812500 joules

Thus, the car travels with a kinetic energy of 2812500 joules

5 0

3 years ago

You are investigating how objects move when they are dropped from different heights. To collect your data, you drop a 1 kg weigh

ASHA 777 [7]

The time of motion of the 5 kg object will be the same as 1 kg since both objects are dropped from the same height.

The given parameters;

<em>Mass of the first object, m1 = 1 kg</em>

<em>Mass of the second object, m2 = 5 kg</em>

The final velocity of the objects during the downward motion is calculated as follows;

$v_f = v_0 + gt\\\\v_f = 0 + gt\\\\\v_f = gt$

The time of motion of the object from the given height is calculated as;

$h = v_0 t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\gt^2 = 2h\\\\t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g} }$

The time of motion of each object is independent of mass of the object.

Thus, the time of motion of the 5 kg object will be the same as 1 kg since both objects are dropped from the same height.

Learn more about time of motion here: brainly.com/question/2364404

3 0

2 years ago

The compressor on an air conditioner draws 66.1 a when it starts up. the start-up time is about 0.388 s. how much charge passes

Ierofanga [76]

The current intensity is defined as the amount of charge flowing through a certain point of a wire divided by the time interval:
$I= \frac{Q}{\Delta t}$
where Q is the charge and $\Delta t$ is the time. Re-arranging the formula, we have
$Q=I \Delta t$

for the compressor in our problem, the intensity of current is I=66.1 A, while the time is $\Delta t= 0.388 s$ , so the amount of charge that crosses a certain point of the circuit during this time is
$Q=I \Delta t=(66.1 A)(0.388 s)=25.65 C$

5 0

3 years ago

Marine magnetic anomalies result from seafloor spreading in conjunction with

Artemon [7]

Earths magnetic field

7 0

3 years ago