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KatRina [158]
3 years ago
9

A climber pulls herself 8 meters upwards with a force of 150 Newtons. If it takes her 16 seconds to cover the 8 meters, how much

power is she using?
Physics
1 answer:
mr Goodwill [35]3 years ago
3 0

Answer:

 P = 75 W

Explanation:

given,

Distance, L = 8 m

Force,F = 150 N

Time, t = 16 s

Work by the climber

Work done = Force x displacement

W = F. L

W = 150 x 8

W = 1200 J

We know,

Power =\dfrac{Work\ done}{time}

P =\dfrac{1200}{16}

 P = 75 W

Hence, Power climber is using to climb is equal to 75 W.

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(A) The spring constant is <u>98 N/m.</u>

(B) The period of oscillation is <u>0.635 s.</u>

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Given:

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Extension length of the spring is, x=10\ cm=0.1\ m

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So, weight of the body is given as:

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Hence, the spring constant is 98 N/m.

(B)

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Therefore, the period of oscillation is 0.635 s.

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