A climber pulls herself 8 meters upwards with a force of 150 Newtons. If it takes her 16 seconds to cover the 8 meters, how much
1 answer:
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Answer:
The distance between the ships changing at 6PM is 21.29Km/h
Explanation:
Ship A is sailing east at 35Km/h and ship B is sailing West at 25Km/h
Given
dx/dt= 35
dy/dt= 25
dv/dt= ???? at t= 6PM - 2PM= 4
Therefore t=4
We know ship A travels at 150km in the x-direction and Ship A at t=4 travels at 4.35 Which is 140 also in x-direction
So, we use:
;
But ship B travels at t=4, at 4.25 =100 in the y-direction
so, let's use the equation:
Lets use 2DD' = 2xx' + 2yy'
Differentiating with respect to t we have:
D•d(D)/dt = -(10)•dx/dt + 100•dy/dt
=100.5 d(D)/dt = (-10)•35 + (100)•25
When t=4, we have x=(140-150) =10 and y=100
=100.5
= 100.5 dD/dt = 10.35 +100.25
= dD/dt = 21.29km/h
Answer:
Distance is 5.0 km and displacement is 0 km.
Explanation:
The diagram is shown below.
Distance is the total length that the truck covers along the complete journey. The truck moves from a stone quarry covering a length of 2.5 km and then again come back to the same point and thus covering another 2.5 km. Therefore, the total length covered by the truck is the sum of forward and backward paths which is equal to 5.0 km.
Now, displacement depends only on the initial and final position. It is given as the difference of final position and initial position. So, the truck starts from stone quarry and returns back to the same position. So, the initial position and final position is same. Therefore, the difference is 0 and hence displacement is zero.
