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PilotLPTM [1.2K]
3 years ago
10

Complete the paragraph to describe the relationship between kinetic energy and braking distance. Use . A car moves at a speed of

50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilometers/hour, then its kinetic energy will be joules. The braking distance at the faster speed is the braking distance at the slower speed.
Physics
2 answers:
Mariana [72]3 years ago
7 0

ke prop to v^2

ke1/v1^2=ke2/v2^2

400/50x50=joules/100x100

400x2x2

1600j

melisa1 [442]3 years ago
3 0

Answer:A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilometers/hour, then its kinetic energy will be 1,600  joules. The braking distance at the faster speed is double the braking distance at the slower speed.

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v_{3f} = - \frac{m*33.9+m*33.9 }{ 2m } \\  \\ v_{3f} = - \frac{2m*33.9 }{ 2m }  \\  \\ v_{3f} = - 33.9m/s

We can see that part of a coconut with biggest mass has same speed as center of mass of two other parts. Negative sign shows that direction is opposite to direction of two pats. Biggest part moves towards north-east.
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