Answer:
82.7 kg
Explanation:
the mass of the boxer remains unchanged, this is because mass is a measure of the quantity of matter in an object irrespective of its location and the gravitational force acting at its location. this means mass is independent of the gravitational acceleration hence it remains the same 82.7 kg. its unit is in kilograms (Kg).
Answer:
-6112.26 J
Explanation:
The initial kinetic energy, 
is given by
} where m is the mass of a body and 
is the initial velocity
The final kinetic energy, 
is given by
where 
is the final velocity
Change in kinetic energy, 
is given by
Since the skater finally comes to rest, the final velocity is zero. Substituting 0 for and 12.6 m/s for and 77 Kg for m we obtain
From work energy theorem, work done by a force is equal to the change in kinetic energy hence for this case work done equals <u>-6112.26 J</u>
Answer:
a) F= 0,19 [N] according to problem statement
b) F = 0,19*10⁹ [N] using the right value of K
Explanation:
The force between two electric charges is according to Coulomb´s law is:
F = K * q₁*q₂ / d² where q₁ and q₂ are the charges on body one and body 2 respectively, d is the distance between the two bodies and K is a constant K = 8,988100*10⁹ N.m²/C². The problem establishes to use K = 8,988100 N.m²/C².
NOTE: To value of is : K = 8,988100*10⁹ N.m²/C². I am going to solve the problem using K = 8,988100 N.m²/C² if that information was an error, all we need to get the right answer is multiply the result by 10⁹
Then:
F = 8,988100 * 1,2* 0,36 / (4,5)² [ N*m²/C² ] * [ C*C*/m²]
F = 3,882859/ 20,25 [N]
F= 0,19 [N]
The force is of repulsion since the two charges are positive and in the direction of the straight line which passes through the centers of the bodies
Answer:
Explanation:
By conservation of the linear momentum:
m1*V1 = (m1+m2)*V2
Solving for V2:
The kinetic energies are:
Simplifying:
The ratio will be:
Answer:
Explanation:
Given that,
Mass per unit length is
μ = 4.87g/cm
μ=4.87g/cm × 1kg/1000g × 100cm/m
μ = 0.487kg/m
Tension
τ = 16.7N
Amplitude
A = 0.101mm
Frequency
f = 71 Hz
The wave is traveling in the negative direction
Given the wave form
y(x,t) = ym• Sin(kx + ωt)
A. Find ym?
ym is the amplitude of the waveform and it is given as
ym = A = 0.101mm
ym = 0.101mm
B. Find k?
k is the wavenumber and it can be determined using
k = 2π / λ
Then, we need to calculate the wavelength λ using
V = fλ
Then, λ = V/f
We have the frequency but we don't have the velocity, then we need to calculate the velocity using
v = √(τ/μ)
v = √(16.7/0.487)
v = 34.29
v = 5.86 m/s
Then, we can know the wavelength
λ = V/f = 5.86 / 71
λ = 0.0825 m
So, we can know the wavenumber
k = 2π/λ
k = 2π / 0.0825
k = 76.18 rad/m
C. Find ω?
This is the angular frequency and it can be determined using
ω = 2πf
ω = 2π × 71
ω = +446.11 rad/s
D. The angular frequency is positive (+) because the direction of propagation of wave is in the negative direction of x
