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3 years ago

8

Which set of elements has 4 valence electrons?

1 answer:

pickupchik [31]3 years ago

4 0

Answer:

carbon group

All the carbon group atoms, having four valence electrons, form covalent bonds with nonmetal atoms; carbon and silicon cannot lose or gain electrons to form free ions, whereas germanium, tin, and lead do form metallic ions but only with two positive charges.

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Are biohazard people real or just video games?

Nadusha1986 [10]

Answer:

Yes, they are real.

Explanation:

Can a human be a biohazard?

Biohazards are any material that can possibly contain infectious diseases. For example, human feces can contain diseases such as C. diff, Hepatitis A and E, Giardia, E coli, Cholera, and Norovirus so, yes, human feces are a biohazard.

also c o v i d

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2 years ago

1. Describe what an irreversible change is.

lozanna [386]

Answer:

A change is called irreversible if it cannot be changed back again. In an irreversible change, new materials are always formed.

Explanation:

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3 years ago

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Which of the following is/are considered alcohols?

Paladinen [302]

Answer: THE ANSWER IS D

Explanation:

an alcohol is a hydrocarbon chain with an hydroxyl group (OH)

A, B, AND C ARE ALL ALCOHOLS, SO THE ANSWER IS D

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3 years ago

Why does magnesium chloride have a much higher melting point than hydrogen chloride ?

pshichka [43]

Because chloride is more reactive than hydrogen.

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3 years ago

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For the following reaction, 22.9 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas. nitrogen monox

ololo11 [35]

Answer:

1) Maximun ammount of nitrogen gas: $m_{N2}=10.682 g N_2$

2) Limiting reagent: $NO$

3) Ammount of excess reagent: $m_{N2}=4.274 g$

Explanation:

<u>The reaction </u>

$2 NO (g) + 2 H_2 (g) \longrightarrow N_2 (g) + 2 H_2O (g)$

Moles of nitrogen monoxide

Molecular weight: $M_{NO}=30 g/mol$

$n_{NO}=\frac{m_{NO}}{M_{NO}}$

$n_{NO}=\frac{22.9 g}{30 g/mol}=0.763 mol$

Moles of hydrogen

Molecular weight: $M_{H2}=2 g/mol$

$n_{H2}=\frac{m_{H2}}{M_{H2}}$

$n_{H2}=\frac{.5.8 g}{2 g/mol}=2.9 mol$

Mol rate of H2 and NO is 1:1 => hydrogen gas is in excess

1) <u>Maximun ammount of nitrogen gas</u> => when all NO reacted

$m_{N2}=0.763 mol NO* \frac{1 mol N_2}{2 mol NO}*\frac{28 g N_2}{mol N_2}$

$m_{N2}=10.682 g N_2$

2) <u>Limiting reagent</u>: $NO$

3) <u>Ammount of excess reagent</u>:

$m_{N2}=(2.9 mol - 0.763 mol NO* \frac{1 mol H_2}{1 mol NO})*\frac{2 g H_2}{mol H_2}$

$m_{N2}=4.274 g$

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3 years ago