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2 years ago

Which set of elements has 4 valence electrons?

Chemistry

1 answer:

pickupchik [31]2 years ago

4 0

Answer:

carbon group

All the carbon group atoms, having four valence electrons, form covalent bonds with nonmetal atoms; carbon and silicon cannot lose or gain electrons to form free ions, whereas germanium, tin, and lead do form metallic ions but only with two positive charges.

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Which kind of nuclear decay does not alter the identity of the atom?

PtichkaEL [24]

For alpha and beta decay it does because the proton number changes.
During gamma, there is no change of identity, just energy

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2 years ago

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Identify the statement that accurately describes ATP

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Adenosine triphosphate

In science, ATP stands for adenosine triphosphate. This chemical, discovered in the 1920s, is important to all life. It stores and releases energy for many cellular processes. It is found in mitochondria.

Explanation:

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2 years ago

What is the chemical formula for the dancing gummy bear<br>

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2 years ago

Which best describes the relationship between the circulatory system and the respiratory system?

Fofino [41]

Answer:

<h3>THE CORRECT ANSWER IS</h3><h3>THE CIRCULATORY SYSTEM IS THE TRANSPORT SYSTEM FOR THE RESPIRATORY SYSTEM.</h3>

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2 years ago

Magnesium (used in the manufacture of light alloys) reacts with iron(III) chloride to form magnesium chloride and iron. A mixtur

yuradex [85]

<u>Answer:</u> The limiting reactant is magnesium and mass of excess reactant present in the vessel is 96.35 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

<u>For magnesium:</u>

Given mass of magnesium = 41.0 g

Molar mass of magnesium = 24 g/mol

Putting values in equation 1, we get:

$\text{Moles of magnesium}=\frac{41.0g}{24g/mol}=1.708mol$

<u>For iron(III) chloride:</u>

Given mass of iron(III) chloride = 175.0 g

Molar mass of iron(III) chloride = 162.2 g/mol

Putting values in equation 1, we get:

$\text{Moles of iron(III) chloride}=\frac{175g}{162.2g/mol}=1.708mol$

The chemical equation for the reaction of magnesium and iron(III) chloride follows:

$3Mg+2FeCl_3\rightarrow 3MgCl_2+2Fe$

By Stoichiometry of the reaction:

3 moles of magnesium reacts with 2 moles of iron(III) chloride

So, 1.708 moles of magnesium will react with = $\frac{2}{3}\times 1.708=1.114mol$ of iron(III) chloride

As, given amount of iron(III) chloride is more than the required amount. So, it is considered as an excess reagent.

Thus, magnesium is considered as a limiting reagent because it limits the formation of product.

Moles of excess reactant left (iron(III) chloride) = [1.708 - 1.114] = 0.594 moles

Now, calculating the mass of iron(III) chloride from equation 1, we get:

Molar mass of iron(III) chloride = 162.2 g/mol

Moles of iron(III) chloride = 0.594 moles

Putting values in equation 1, we get:

$0.594mol=\frac{\text{Mass of iron(III) chloride}}{162.2g/mol}\\\\\text{Mass of iron(III) chloride}=(0.594mol\times 162.2g/mol)=96.35g$

Hence, the limiting reactant is magnesium and mass of excess reactant present in the vessel is 96.35 grams.

6 0

3 years ago