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polet [3.4K]
3 years ago
10

On planet X, an object weighs 7.04 N. Onplanet B where the magnitude of the free-fallacceleration is 1.91g(whereg= 9.8 m/s2isthe

gravitational acceleration on Earth), theobject weighs 25.74 N.The acceleration of gravity is 9.8 m/s2.What is the mass of the object be on Earth?Answer in units of kg.
Physics
1 answer:
timurjin [86]3 years ago
4 0
<h2>Mass of object in Earth is 1.37 kg</h2>

Explanation:

On planet B where the magnitude of the free-fall acceleration is 1.91g , the object weighs 25.74 N.

We have

           Weight = Mass x Acceleration due to gravity

On planet B

           25.74 = Mass x 1.91 g

           25.74 = Mass x 1.91 x 9.81

           Mass = 1.37 kg

Mass is constant for an object. It will not change with location.

Mass of object in Earth = Mass of object in Planet B

Mass of object in Earth = 1.37 kg

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A motorcycle is moving at a constant speed of 45km/h how long does it take the motorcycle to travel a distance of 20km?
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Answer:

It takes 1600 seconds or \frac{4}{9} hours to travel a distance of 20 km.

Explanation:

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Speed of the motorcycle, v=45\textrm{ km/h}

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We know that,

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Plug in 20 km for D and 45 km/h for v. Solve for time.

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Answer:

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Explanation:

In the given system the angular momentum of the system is conserved

initial angular momentum of the system

L_{i}=I_{1}\omega _{1}\\\\\omega _{1}=\frac{8\pi }{15}rad/sec\\\\I_{1}=\frac{1}{2}mr^{2}+(m_{1}+m_{2}+m_{3})r^{2}\\\\I_{1}=\frac{1}{2}\times 105\times 1.8^{2}+(33+28+28) \times 1.8^{2}=458.46kgm^{2}\\\\\therefore L_{i}=458.46\times \frac{8\pi }{15}=768.16

When 28 kg child moves to the center the moment of inertia changes thus we have

I_{2}=\frac{1}{2}mr^{2}+(m_{1}+m_{2})r^{2}\\\\I_{1}=\frac{1}{2}\times 105\times 1.8^{2}+(33+28) \times 1.8^{2}=367.74kgm^{2}\\\\\therefore L_{f}=367.74\times \omega _{f}

Equating initial and final angular momentum we get

I_{2}=\frac{1}{2}mr^{2}+(m_{1}+m_{2})r^{2}\\\\I_{1}=\frac{1}{2}\times 105\times 1.8^{2}+(33+28) \times 1.8^{2}=367.74kgm^{2}\\\\\therefore L_{f}=367.74\times \omega _{f}\\\\\omega _{f}=\frac{768.16}{367.74}=2.1rad/sec\\\\N_{2}=19.95rpm

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