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s344n2d4d5 [400]
3 years ago
12

Write two different unit in which mass is measured.​

Physics
1 answer:
inessss [21]3 years ago
5 0

Answer:

kilograms and grams

Explanation:

kilograms is the stadard unit for mass according to the SI system.

Grams is another unit for mass.

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irakobra [83]

Answer:

The mass of the block, M =T/(3a +g)  Kg

Explanation:

Given,

The upward acceleration of the block a = 3a

The constant force acting on the block, F₀ = Ma = 3Ma

The mass of the block, M = ?

In an Atwood's machine, the upward force of the block is given by the relation

                                     Ma = T - Mg

                                      M x 3a = T - Ma    

                                    3Ma + Mg = T

                                       M = T/(3a +g)  Kg

Where 'T' is the tension of the string.

Hence, the mass of the block in Atwood's machine is, M = T/(3a +g)  Kg

3 0
3 years ago
Read 2 more answers
Pressure and volume changes at a constant temperature can be calculated using
V125BC [204]

Answer:

Option A, Boyle's law

Explanation:

The complete question is

Pressure and volume changes at a constant temperature can be calculated using

a. Boyle's law. c. Kelvin's law.

b. Charles's law. d. Dalton's law.

Solution

In Boyle’s law, the gas is assumed to be ideal gas and at constant  temperature. With these two conditions fixed, Boyle’s established that volume of gas varies inversely with the absolute pressure.  

The basic mathematical representation of this phenomenon is as follows -  

P \alpha \frac{1}{V}

OR

P = \frac{k}{V} \\PV = k

Where P is the pressure of ideal gas, V is the volume and k is the constant of proportionality.

Hence, option A is correct

3 0
3 years ago
The drinking water needs of an office are met by cooling tab water in a refrigerated water fountain from 23 to 6°C at an average
Ratling [72]

Answer:

The correct option is;

(c) 64W

Explanation:

Here we have the Coefficient Of Performance, COP given by

COP = \frac{Q_{cold}}{W} = 3.1

The heat change from 23° to 6°C for a mass of 10 kg/h which is equivalent to 10/(60×60) kg/s or 2.78 g/s we have

Q_{cold} = m·c·ΔT = 2.78 × 4.18 × (23 - 6) = 197.39 J

Therefore, plugging in the value for  Q_{cold} in the COP equation we get;

COP = \frac{197.39 }{W} = 3.1 which gives

W =  \frac{197.39 }{3.1} = 63.674 \ J

Since we were working with mass flow rate then the power input is the same as the work done per second and the power input to the refrigerator = 63.674 J/s ≈ 64 W.

The power input to the refrigerator is approximately 64 W.

4 0
3 years ago
Read 2 more answers
What the opposite of suspension physical science physical science
Svetlanka [38]
A colloid I think. Don’t hold it against me if I’m wrong my dude.
4 0
3 years ago
What muscle movement do we use to close a joint.
marin [14]

Answer: Your using your skeletal muscle

Explanation:

3 0
3 years ago
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